1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide. CH₂CH₂CH₂CH₂OH (1)→ CH3 CH₂CH₂CH₂Br (1) If 17.12 ml of 1-butanol produced 14.77 g of 1-bromobutane, the percentage yield of the product equals: (Assume the density of 1-butanol is 0.81 g/mL, the molar mass of 1-butanol is 74 g/mol, and the molar mass of 1-bromobutane is 137 g/mol.)

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Chapter10: Fuels, Organic Chemicals, And Polymers
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1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide.
CH₂CH₂CH₂CH₂OH (1)→ CH3 CH₂CH₂CH₂Br (1)
If 17.12 mL of 1-butanol produced 14.77 g of 1-bromobutane, the percentage yield of the product equals:
(Assume the density of 1-butanol is 0.81 g/mL, the molar mass of 1-butanol is 74 g/mol, and the molar mass of 1-bromobutane is 137 g/mol.)
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Transcribed Image Text:1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide. CH₂CH₂CH₂CH₂OH (1)→ CH3 CH₂CH₂CH₂Br (1) If 17.12 mL of 1-butanol produced 14.77 g of 1-bromobutane, the percentage yield of the product equals: (Assume the density of 1-butanol is 0.81 g/mL, the molar mass of 1-butanol is 74 g/mol, and the molar mass of 1-bromobutane is 137 g/mol.) Submit Answer Try Another Version 1 item attempt remaining
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