(1) A plastic piece was being analyzed by flotation methods. The piece of plastic was suspended in a solution which had an equivalent density. 8.26 mL of this solution were placed into a measuring device that had an empty mass of 43.33 g. The new mass of the device and solution was 52.17 g. Use this information and determine the density of the plastic (i.e., same as the density of solution!). (note, i.e. stands for "id est" in Latin. It is identical to "that is" in English)
(1) A plastic piece was being analyzed by flotation methods. The piece of plastic was suspended in a solution which had an equivalent density. 8.26 mL of this solution were placed into a measuring device that had an empty mass of 43.33 g. The new mass of the device and solution was 52.17 g. Use this information and determine the density of the plastic (i.e., same as the density of solution!). (note, i.e. stands for "id est" in Latin. It is identical to "that is" in English)
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter16: Solutions
Section: Chapter Questions
Problem 16.3TC
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Transcribed Image Text:(1)
A plastic piece was being analyzed by flotation methods. The piece of plastic was suspended in
a solution which had an equivalent density. 8.26 mL of this solution were placed into a
measuring device that had an empty mass of 43.33 g. The new mass of the device and solution
was 52.17 g. Use this information and determine the density of the plastic (i.e., same as the
density of solution!). (note, i.e. stands for "id est" in Latin. It is identical to "that is" in English)
that
Transcribed Image Text:(2)
Use the results calculated in (1) and the Table provided in the introduction to determine the
type of plastic that was analyzed.
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