1:) A circular coagulation basin has a diameter of 2.5 m and it's depth equal to 1.60 m. If me following data are available: Gt=27000, t-30 s, µ-1.003× 10³ kg/m.s,alum dosage= 50 g/l, determine: The required mixing power in unit of (kW). The daily quantity of alum added in unit of (kg/d). 2:) The flow described in (Q1) above is to be flocculated in a basin having four

1:) A circular coagulation basin has a diameter of 2.5 m and it's depth equal to 1.60 m. If me following data are available: Gt=27000, t-30 s, µ-1.003× 10³ kg/m.s,alum dosage= 50 g/l, determine: The required mixing power in unit of (kW). The daily quantity of alum added in unit of (kg/d). 2:) The flow described in (Q1) above is to be flocculated in a basin having four

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Example! A circular Coagulation basin has a diameter of 2.5m and it's depth equal to 1.60m. If the following data are available, Ct = 27000 to 30s M = 1.00 3 * 10 ³ kg/m.s, alum dosage = 50 mg/L Determine 8- 2 The required mixing Power in unit of (kw) The daily quantity of alum added in unit of (kgld)
Q.5. The design flow for a water treatment plant (WTP) is 1 MGD. The rapid mixing tank will have a mechanical mixer and the average alum dosage will be 35 mg/L. the theoretical mean hydraulic detention time of the tank will be 60 seconds. Determine the following: 1-The quantity of alum needed on a daily basis in kg/d, 2-The dimensions of the tank in meters for a tank with equal length, width and depth, 3- The power input required for aggo Go of 900 seê' forawa te Tempreature of lóc (M=1•307*15°N• s/mz express The a $is wer in kw
Given:Flow rate of water = 500 L/minSuspended solids concentration in influent water = 100 mg/LRequired effluent suspended solids concentration = 10 mg/LFiltration rate = 10 m^3/m^2/hrFiltration tank dimensions: Length = 5 m, Width = 3 m, Depth = 4 mCalculate:o Calculate the total suspended solids (TSS) load in the influent water:o Calculate the filtration tank surface area:o Calculate the required filtration tank capacity:o Calculate the required detention time in the filtration tank: Q2) DisinfectionGiven:Flow rate of water = 2000 m^3/hChlorine residual required in effluent = 0.5 mg/LInitial chlorine concentration in influent water = 2 mg/LChlorine decay rate in disinfection tank = 0.05 per hourDisinfection tank volume = 300 m^3Calculate:o Calculate the chlorine demand in the influent water:o Calculate the chlorine dosage required:o Calculate the chlorine dosage rate:o Calculate the actual chlorine dosage rate considering chlorine decay:
Problem 7 - 68 Oil having sp. gr. of 0.9 and viscosity v = 0.0002 m2/s flows upward through an inclined pipe as shown. Determine the flow rate Ans: 7.64 L/s 10 m 6 cm diameter D, = 250 kPa 40 P- 350 kPa
Q1: The design flow for a water treatment plant (WTP) is 1 MGD (3.8x10 m³ /d). The rapid mixing tank will have a mechanical mixer and the average alum dosage will be 30 mg/L. The theoretical mean hydraulic detention time of the tank will be 1 minute. Determine the following: a) the quantity of alum needed on a daily basis in kg/d, b) the dimensions of the tank in meters for a tank with equal length, width, and depth, c) the power input required for a G of 900 sec' for a water temperature of 10 °C. Express the answer in kW, given that u = 1.307 × 10³Kg/m.s.
A tank is initially filled to capacity with 300 L pure water. At t=0, brine containing 2 g/L salt is pumped into the tank at a rate of 25 L/min. The well-mixed solution is pumped out at a larger rate of 50 L/min. Determine the concentration of the salt inside the tank after 5 min. Use dQ/dt = ci vi - co vo as a formula
Problem 7 - 68 Oil having sp. gr. of 0.9 and viscosity v= 0.0002 m²/s flows upward through an inclined pipe as shown. Determine the flow rate Ans: 7.64 L/s 10 m 6 6 cm diameter D) = 250 kPa 40 0 P₁ = 350 kPa
2. (a) Design a gravity thickener to concentrate the mixture of sludge obtained from primary and secondary settling units in an activated sludge wastewater treatment plant. Make appropriate assumptions in your calculations. Sludge waste flow rate in the primary settling unit= 140 m³/d; and concentration = 2.5% Sludge waste flow rate in the secondary settling unit= 350 m/d; and concentration = 0.6% Qi ci Solids Loading Rate (SLR) = 40 kg ds / m².d, and SLR : A ci Qi Tc Expression for thickening zone depth= 0.75Cu A Ci: Incoming mixed sludge concentration Qi: Incoming mixed sludge flow rate A: Cross section area of the thickening tank Cu: Target underflow concentration (=5%) Tc: Time in compression zone (=2 days)
Suppose that 1-L graduated cylinder in the figure as shown below contains a sludge of 1 percent solids. Now suppose that all of the solids are allowed to settle and that the liquid is decanted until the total volume is 500 ml. The new solid fraction is 1000 mL 750 mL 500 mL 250 mL (a) (b) (c)
A completely mixed activated sludge process operating at equilibrium is designed to treat 300 MLD of waste water. The influent and effluent BOD are 200 mg/1 and 18 mg/1 respectively If the F M then the hydraulic retention time is A 0.125 day B 4.21 hours C 8.42 hours D 0.225 day = 0.3 and MLSS is 3800 mg/1,
Gave wrong values earlier. These are the correct values A settling tank having a depth of 3.5 m and surface area of 1000 m2 is used to remove particles of size 0.01 mm and specific gravity of 2.6. Calculate the removal percentage of the tank for the discharge of 7000 m3/d. Take viscosity of water as 1.1x10-3 kg/m.s.
The data of an activated sludge process are 3. as follows: MLSS = 5000 mg/lit %3D Flow = 0.15 m3/sec SS of inflow = 400 mg/lit Solids settled after 30 min = 25% %3D Volume of Aeration Tank = 3000m3 %3D Sludge Wastage Rate = 120 m³/day with VSS of 15000 mg/lit. %3D Calculate Sludge Volume Index (SVI), Sludge Density Index (SDI), Return Sludge Ratio (Qp/Q,) and Mean cell residence time (0,).