(-1)" 5n 1 Determine whether the series converges absolutely convcrges conditionally, n=1 diverges. or

4" – 3n Determine whether the series 2 converges or diverges. If it converges, find its sum. 5" n=0

Determine convergence or divergence of the alternating series. (-1)n n=1 5n3 +1 Converges Diverges

Determine if the series Σ(-1)" 5n 1/2 + 3 converges 3n² - 3 n=1 absolutely, converges conditionally, or diverges, and justify your answer. The Series ✗(-1)" 5n / 2 +3 3n² - 3 n=1 converges by the since the absolute value of the terms Consider the absolute value of 5N 1/1 2 + 3 the series: 3n² - 3 n=1 by the to the p- series with p = which since a p-series will く if and only if n=1 5n³½ + 3 3m² - 3 and ☑ n=1 Since (−1)n 5n1/2 + 3 3n² - 3 Σ(-1)" n=1 5n 1/2 + 3 3n² - 3 > >