01omog doiiw am llor be Before collision V2 Top of swing Immediately after collision mg + mw

. What is the initial kinetic energy in joules of the bullet in problem 1? What is the final kinetic energy of the combined bullet/pendulum?

Cons Block 1, of mass m1 = 2.90 kg , moves along a frictionless air track with speed vị with block 2, of mass m2 = 57.0 kg , which was initially at rest. The blocks stick together after the collision. (Figure 1) 13.0 m/s. It collides %3D Part A Part B Part C What the change AK = Kfinal – Kiniti. in the two-block system's kinetic energy due the collision? Express your answer numerically in joules. • View Available Hint(s) Figure 1 of 1 HV ΑΣφ ? Before collision: m2 m1 AK = 1 Submit After collision: Provide Feedback 1 2.

A 61g ball traveling at 6.3 m/s is caught by a 220g pendulum bob. The center of mass of the pendulum / ball system reaches a maximum height of 10.4 cm (relative to the initial rest position) after the collision. Calculate the kinetic energy of the pendulum/ball system in the instant after the collision (Kball+bob). Use L=30.2cm and R=26.3cm

A bullet, with mass 0.008 kg is fired into a block of wood with mass 1.96 kg suspended like a pendulum. The bullet makes a completely inelastic collision with the block, becoming embedded in it. After the impact of the bullet, the block swings up to a maximum height 0.079 m. Find the initial speed of the bullet? a) DVB V₂ Δε C M ب 6) /// hJ دو ► M+m

QIIII: A thin uniform rod of mass Mr and length L is suspended from the ceiling and mounted on a horizontal frictionless axle at the top. The rod is initially at rest in its equilibrium position when a ball of play dough, of mass mb, strikes the rod at its lower end and remains stuck to the rod. The sticky ball is thrown with an initial speed v0 at a 60 degree angle from the horizontal direction, and strikes the rod when it reaches the top of its trajectory, as shown in Fig.4. The acceleration due to gravity has magnitude g and air resistance is negligible.  a. Determine the velocity of the ball of play dough right before it sticks to the rod. Use the x- y coordinate system defined in Fig.4.   b. Determine the angular velocity of the rod+ball system right after the collision. Take counterclockwise as positive.   c. - Establish the differential equation satisfied by the rod+ball system after the collision and determine the angular frequency of the system. You may assume that the small…

A 11 g bullet is fired into the bob of a ballistic pendulum of mass 1.3 kg. When the bob is at its maximum height, the strings make an angle of 60° with the vertical. The length of the pendulum is 2.3 m. Find the speed of the bullet. m/s еВook

A billiard ball moving at 5.20 m/s strikes a stationary ball of the same mass. After the collision, the first ball moves at 4.67 m/s at an angle of 26.0° with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), find the struck ball's velocity after the collision. magnitude direction 1.56 × Check the initial and final kinetic energies. You will find that your final kinetic energy is not equal to the initial kinetic energy. m/s ° (with respect to the original line of motion)

A 1.10-kg wooden block rests on a table over a large hole as shown. A 3.70 x 102 kg bullet is fired with an initial velocity v = 591 m/s upward into the bottom of the block, collides inelastically with it, and remains embedded in the block after the collision. To what maximum height does the block-bullet system rise after the collision? {consider a completely/perfectly inelastic collision and conservation of energy 'system'} 08.33 m O 12.0 m O 29.8 m O 18.9 m O22.1 m 4. LE B M command command option

In a ballistic pendulum experiment, a small marble is fired into a cup attached to the end of a pendulum. If the mass of the marble is 0.0235 kg and the mass of the pendulum is 0.250 kg, how high ℎ will the pendulum swing if the marble has an initial speed of 5.95 m/s? Assume that the mass of the pendulum is concentrated at its end so that linear momentum is conserved during this collision.