Could you solve the problem in the picture below? Fat tCaleutYeforemedian 11.5 The Motion(Fig Plounted oent for anwho afore the meeting, is disappointed that he cannotnod the meeting, and his mood sours even further byNe boring experiment in which every time interval forhe dropped ball is identical for the entire eveningMA 0,005 00-kg bullet traveling horizontally with100 x 10 m/s strikes an 18.0-kg door, embedding itself10.0 cm from the side opposite the hinges as shown inFigure Pl1.41. The 1.00-m wide door is free to swingon its frictionless hinges. (a) Before it hits the door,does the bullet have angular momentum relative to thedoor's axis of rotation? (b) If so, evaluate this angu-lar momentum. If not, explain why there is no angularmomentum. (c) Is the mechanical of the bullet-door system constant during this collision? Answerwithout doing a calculation. (d) At what angular speedspeedA.4.SO,energyOSTdoes the door swing open immediately after the colli-Sion? (e) Calculate the total energy of the bullet-doorsystem and determine whether it is less than or equalto the kinetic energy of the bullet before the collision.Hingelocir45.18.0kg0.005 00 kgCSectionits42. A46. ReTonsepaSeds

Answered: Image /qna-images/answer/56c11bdc-bfcf-4d67-ad5f-e7fda64e4091.jpg

0005 00-kg bullet traveling horizontally with speed MX 10 m/s strikes an 18.0-kg door, embedding itself 10.0 cm from the side opposite the hinges as shown in Figure Pl1.41. The 1.00-m wide door is free to swing on its frictionless hinges. (a) Before it hits the door, loes the bullet have angular momentum relative to the door's axis of rotation? (b) If so, evaluate this angu- lar momentum. If not, explain why there is no angular momentum. (c) Is the mechanical energy of the bullet- door system constant during this collision? Answer without doing a calculation. (d) At what angular speed does the door swing open immediately after the colli- Sion? (e) Calculate the total energy of the bullet-door system and determine whether it is less than or equal to the kinetic energy of the bullet before the collision.

0005 00-kg bullet traveling horizontally with speed MX 10 m/s strikes an 18.0-kg door, embedding itself 10.0 cm from the side opposite the hinges as shown in Figure Pl1.41. The 1.00-m wide door is free to swing on its frictionless hinges. (a) Before it hits the door, loes the bullet have angular momentum relative to the door's axis of rotation? (b) If so, evaluate this angu- lar momentum. If not, explain why there is no angular momentum. (c) Is the mechanical energy of the bullet- door system constant during this collision? Answer without doing a calculation. (d) At what angular speed does the door swing open immediately after the colli- Sion? (e) Calculate the total energy of the bullet-door system and determine whether it is less than or equal to the kinetic energy of the bullet before the collision.

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter2: Vectors

Section: Chapter Questions

Problem 2.9CYU: Check Your Understanding Suppose that Balto in Example 2.10 leaves the game to attend to more...

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