0.5m Q6) Newton's 2nd Law of Rotation and Angular Momentum 4.8m/s² 2kg A string is wrapped around a heavy wheel of radius R = 0.5 m. A block of mass m = 2 kg hangs from the other end of the string. When let go, the block falls with an acceleration of a = 4.8 m/s². The wheel rotates about its center with angular acceleration a, but otherwise does not move. The string does not slip. a) Draw a free body diagram and write Newton's 2nd law for the block Do not substitute any numbers. b) Draw a free body diagram and write Newton's 2nd law for the wheel. Do not substitute any numbers. c) What is the tension in the string, T? Write your answer to two decimal places d) What is the angular acceleration, a? Write your answer to two decimal places. e) What is the moment of inertia of the heavy wheel? Write your answer to two decimal places. f) The ice caps are found near the North and South poles of the Earth. If the ice caps were to melt, the water would spread out across all the oceans. What would happen? Put an X in the correct answer for each statement. No explanation required. Increase The moment of inertia of the earth would: The angular momentum of the earth would: The angular velocity of the earth would: The length of a day would: Decrease Stay the same

What is the magnitude of the angular momentum of the 2.40 kgkg , 4.20-cm-diameter rotating disk in the figure (Figure 1)?

Find IOG, The mass moment of inertia for the center of mass about the z′ axis is Iz′z′G=494.6 kg⋅m2

7. A 0.25 kg bullet is fired with a velocity of 200 m/s into two spheres mounted on a shaft with a vertical axis of rotation (coming out of the page) the spheres rotate horizontally. Each sphere has a mass of 0.80 kg and can be treated as a point mass. The mass of the shaft can be ignored. The bullet hits one of the spheres at the angle shown and sticks to the sphere which starts at rest. 30° Axis Of Rotation a. Determine the linear momentum of the bullet. b. Determine the angular momentum of the bullet/spheres system after the bullet hits the sphere. (Remember, momentum is conserved so you can calculate the momentum of the system at any time as long as you include all of the pieces.) 0.50 m