0.3 m 3 m (a) N(y) W(y) (b)

can you help answer this question please? thank you.

-1 m 1m Draw a Free-Body Diagram of the bars AD and BC shown in the figure. Assume all 1m 500 N hinges to be smooth and neglect the weight of each bars. 1 m B.

A uniform edge load of w1 = 530 lb/in. and w2 = 320 lb/in. is applied to the polystyrene specimen. Ep = 597(103)psi and νp = 0.25. 1) Part A: If the specimen is originally square and has dimensions of a = 1 in ., b = 2 in., and a thickness of t = 0.35 in. , determine its new dimension a′ after the load is applied. 2) Part B: Determine its new dimension b′ after the load is applied. 3) Part C: Determine its new dimension t′ after the load is applied.

The timber member has a cross-sectional area of 1703 mm2 and its modulus of elasticity is 13.2 GPa. Compute the change in the total length (in mm) of the member after the loads shown are applied if x = 1.84, y = 3.63, and z = 4.11. Round off the final answer in two decimal places.

Determine the angle that will yield a maximum force uh member BC, along with magnitude and nature of this force. Note: use method of sections and show solution. Answer should be 45° & BCmax = 168 kN

Q) For the shown truss, determine the stiffness matrix of member 1 (1 to 3) and member 2 (2 to 3)? Let A = 50X10 m² and E-210 GPa for all elements. 50 KN 30 m - 3 20 m 100 KN 30 m 40 m

q1 The steel block shown in is subjected to a compressive force on all directions. Determine the change in length of Z-direction if the change in length of Y- direction is (-1.3mm). E for steel =210*10° N/mm? and u=0.28). 20cm 10cm F Scm F

The pyramidal truss section BCDEF is symmetric about the vertical x-z plane as shown. Cables AE, AF, and AB support a 3.3-kN load. Determine the force in member BE. The force is positive if in tension, negative if in compression. 220 mm 220 mm 270 mm 270 mm 350 mm Answer: BE= i 290 с 290 mum 2.1kn kN

In the loaded truss shown :- AB=BC=CD=DE=2.8m, BF=CG=GI=DH=HJ=EK/2=4.2m. If the loading P=3.5kN, Calculate force in HK.