:0: -H+H3C-Br: In Reaction 2, the reactant HO™ is a: Lewis base Nucleophile Brønsted base H3C :O: The reactant CH3 Br is a: Brønsted acid Nucleophile Lewis acid
Ionic Equilibrium
Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.
Arrhenius Acid
Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red.
Bronsted Lowry Base In Inorganic Chemistry
Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.
For this reaction I attempted to answer them but I got it wrong, and was wondering why? Wouldn't HO- be the bronsted acid since it's accepting the H from the Br, which makes the CH3Br give away the carbon and hydrogens? which is the bronsted acid?
![**Reaction 2:**
\[ \cdot\cdot \overset{:\cdot}{\text{O}}{\dashv\text{H}} + \text{H}_3\text{C}{-}\overset{\cdot\cdot}{\overset{:}{\text{Br}}} \rightarrow \text{H}_3\text{C}{-}\overset{:}{\text{O}}{\dashv\text{H}} + {\overset{\cdot\cdot}{\overset{:\cdot}{\text{B}}}\overset{\cdot\cdot}{\overset{:}{\text{r}}}} \]
**In Reaction 2, the reactant HO⁻ is:**
- ☐ Lewis base
- ☑ Nucleophile
- ☑ Brønsted base
**The reactant CH₃Br is:**
- ☑ Brønsted acid
- ☐ Nucleophile
- ☐ Lewis acid
**Explanation:**
In this reaction, the hydroxide ion (HO⁻) acts as a nucleophile and a Brønsted base, donating a pair of electrons to form a bond while also accepting a proton (H⁺) from CH₃Br. The CH₃Br molecule is acting as a Brønsted acid, providing the proton to the hydroxide ion.
The reaction leads to the formation of methanol (CH₃OH) and a bromide ion (Br⁻). The diagram uses dots to indicate electron pairs and shows the movement of electrons from the nucleophile to the electrophile through curved arrows.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8acd4021-f643-407d-9d42-7124cf5151d6%2F1b33b196-2962-40ad-acd8-4c0f4b3dbb01%2F4850g1_processed.png&w=3840&q=75)
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