0 + 1/ 0 - 1/10 0 1 O (-4,1)✔ 2 (-2,3) 0 Let f be the continuous function defined on [-4, 3] whose graph, consisting of three line segments and a semicircle centered at the origin, is given above. Let g be the function given by g (x) = f₁ f (t) dt. Find the value of g (-2). (1,0) Graph of f (3,-1)

Consider the function f(x) = 6 – 2x on the interval [- 2, 8]. Find the average or mean slope of the function on this interval, i.e. f(8) – f( – 2) 8 - (– 2) By the Mean Value Theorem, we know there exists a c in the open interval ( – 2, 8) such that f'(c) is equal to this mean slope. For this problem, there is only one c that works. Find it.

Consider the function f(x) that is described by the statment: " the function decreases to the point (-3, -2) and then increases to the point (2,4) and then decreases again". [A: 4] A. Sketch f(x) roughly. B. Determine the interval where the first derivative is positive or negative. C. Determine the sign (+/ -) of the value of f" (-3) and f" (2)