
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Hydrogenation of

Transcribed Image Text:.D
D2
Pd-C
н
н
B.
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- Synthesize (Z)-hept-5-en-2-one from ethyl acetoacetate (CH3COCH2CO2Et) and the given starting material. You may also use any other organic compounds or required inorganic reagents.arrow_forward(a) Draw the mechanism for the formation of both of the enols that can be formed from A (use acetic acid & AcOH as the source of the protons) (b) Draw the mechanism of reaction of this enol with bromine to give product Barrow_forwardRibose, a carbohydrate with the formula shown, forms a cyclic hemiacetal, which, in principle, could contain either a four-membered, five-membered, or six-membered ring. When D-ribose is treated with methanol in the presence of an acid catalyst, two cyclic acetals, A and B, are formed, both with molecular formula C,H,0, These are separated, and each is treated with sodium periodate (Section 10.8C) followed by dilute aqueous acid. Both A and B yield the same three products in the same ratios. он о CHO СНО H+ CH,OH A +B ÕH 1. NalO, 2. H,0* НО CHO + CHOH + CH,OH ÕH CH,OH Isomeric cyclic acetals with molecular formula CH12O, D-Ribose (C;H1605) From this information, deduce whether the cyclic hemiacetal formed by D-ribose is four- membered, five-membered, or six-membered.arrow_forward
- 1. (a) Propose structure of the major product when A is reacted with dil. H2SO4. (b) Propose a mechanism for the reaction. Show all intermediate structures and all electron flow with arrows. OH dil. H2SO4arrow_forward1,2-Diols are converted to carbonyl compounds when treated with strong acids, in a reaction called the pinacol rearrangement. (a) Draw a stepwise mechanism for this reaction. (Hint: The reaction proceeds by way of carbocation intermediates.) (b) Assuming that the pinacol rearrangement occurs via the more stable carbocation, draw the rearrangement product formed from diol D.arrow_forwardDevise a synthesis of CH3CH2C≡CCH2CH2CH3using CH3CH2CH=CH2as the starting material. You may use any other organic compounds or inorganic reagents.arrow_forward
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