.0. One kg-mol of oxygen undergoes a reversible non-flow isothermal compression and the volume decreases from 0.2 m³/kg to 0.08 m³/kg and the initial temperature is 60°C. If the gas obeys Van der Waal's equation, find (a) the work done during the process (b) the final pressure. For 02 : a = 139250 Nm*/(kg mol)?, b=0.0314 m³/kg mol, Ro=8314 Nm/kg-mol. [W=-2524723 Nm/kgmol, p= 10.736 bar]
.0. One kg-mol of oxygen undergoes a reversible non-flow isothermal compression and the volume decreases from 0.2 m³/kg to 0.08 m³/kg and the initial temperature is 60°C. If the gas obeys Van der Waal's equation, find (a) the work done during the process (b) the final pressure. For 02 : a = 139250 Nm*/(kg mol)?, b=0.0314 m³/kg mol, Ro=8314 Nm/kg-mol. [W=-2524723 Nm/kgmol, p= 10.736 bar]
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![10. One kg-mol of oxygen undergoes a reversible non-flow isothermal compression and the volume
decreases from 0.2 m³/kg to 0.08 m³/kg and the initial temperature is 60°C. If the gas obeys Van der
Waal's equation, find (a) the work done during the process (b) the final pressure. For 02 : a = 139250
Nm*/(kg mol)?, b=0.0314 m³/kg mol, R,=8314 Nm/kg-mol.
[W=-2524723 Nm/kgmol, p= 10.736 bar]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2ac045e7-5e99-41a6-b239-c9c9dc42c748%2F7a870ca7-5b98-47ed-b5b5-7d73788e5a2a%2F035aio_processed.png&w=3840&q=75)
Transcribed Image Text:10. One kg-mol of oxygen undergoes a reversible non-flow isothermal compression and the volume
decreases from 0.2 m³/kg to 0.08 m³/kg and the initial temperature is 60°C. If the gas obeys Van der
Waal's equation, find (a) the work done during the process (b) the final pressure. For 02 : a = 139250
Nm*/(kg mol)?, b=0.0314 m³/kg mol, R,=8314 Nm/kg-mol.
[W=-2524723 Nm/kgmol, p= 10.736 bar]
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