A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
10th Edition
ISBN: 9780134753119
Author: Sheldon Ross
Publisher: PEARSON
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Determine whether the graph shown could represent a variable with a normal distribution. Explain your reasoning. If the
graph appears to represent a normal distribution, estimate the mean and standard deviation.
4
.....
Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice.
O A. The graph could represent a variable with a normal distribution because the curve is symmetric and bell-shaped. Its mean is approximately
and
standard deviation is approximately
(Round to one decimal place as needed.)
O B. The graph could not represent a variable with a normal distribution because the curve crosses the x-axis.
O C. The graph could not represent a variable with a normal distribution because the curve has two modes.
O D. The graph could not represent a variable with a normal distribution because the graph is skewed to the right.
O E. The graph could not represent a variable with a normal distribution because the graph is skewed to the left.
O F. The graph could not represent a variable with a normal distribution because the curve is constant.
Nex
H =[201
70°F
o search
expand button
Transcribed Image Text:Determine whether the graph shown could represent a variable with a normal distribution. Explain your reasoning. If the graph appears to represent a normal distribution, estimate the mean and standard deviation. 4 ..... Select the correct choice below and, if necessary, fill in the answer boxes to complete your choice. O A. The graph could represent a variable with a normal distribution because the curve is symmetric and bell-shaped. Its mean is approximately and standard deviation is approximately (Round to one decimal place as needed.) O B. The graph could not represent a variable with a normal distribution because the curve crosses the x-axis. O C. The graph could not represent a variable with a normal distribution because the curve has two modes. O D. The graph could not represent a variable with a normal distribution because the graph is skewed to the right. O E. The graph could not represent a variable with a normal distribution because the graph is skewed to the left. O F. The graph could not represent a variable with a normal distribution because the curve is constant. Nex H =[201 70°F o search
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