... 4. You are given a string of length > 3. Print the middle 3 characters if the length is odd or the middle 2 characters if the length is even. Strings.java 1 import java.util.Scanner; ebook-bjeo-7-ch04-sec05-cc-2 5 pubtic tlass Strings 4 { public static void main(String[] args) { Scanner in = new Scanner(System.in); 5 6. in.next(); String word = String result = . . . 10 System.out.println(result); } 11 12 13 } CodeCheck Reset
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- Fix the errors and send the code please // Application allows user to enter a series of words // and displays them in reverse order import java.util.*; public class DebugEight4 { public static void main(String[] args) { Scanner input = new Scanner(System.in); int x = 0, y; String array[] = new String[100]; String entry; final String STOP = XXX; StringBuffer message = new StringBuffer("The words in reverse order are\n"); System.out.println("Enter any word\n" + "Enter + STOP + when you want to stop"); entry = input.next(); while(!(entry.equals(STOP))) { array[x] = entry; ++x; System.out.println("Enter another word\n" + "Enter " + STOP + " when you want to stop"); entry = input.next(); } for(y = x - 1; y > 0; ++y) { message.append(array[y]); message.append("\n"); } System.out.println(message) }public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string. This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is, str = new StringBuilder(str).reverse().tostring(); A bit convoluted, but does what is needed without fuss or muss. Maybe one day the Java strings will come with the reverse method built in, just like the string data types of all sensible…Code that need debugging fix with no errors // Gets a String from user // Converts the String to lowercase, and // displays the String's length // as well as a count of letters import java.util.*; public class DebugSeven4 { public static void main(String[] args) { Scanner kb = new Scanner(System.in); String aString ; int numLetters = 0; int stringLength; System.out.println("Enter a String. Include"); System.out.println("some uppercase letters, lowercase"); System.out.print("letters, and numbers >> "); aString = kb.nextLine(); stringLength = aString.length(); System.out.print("In all lowercase, the String is: "); for(int i = 0; i <= stringLength; i++) { char ch = Character.toLowerCase(aStringcharAt(i)); System.out.print(ch); if(!Character.isLetter(ch)) numLetters++; } System.out.println(); System.out.println ("The number of CHARACTERS…
- public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current stringExtend to cast the double to an integer, and output that integer. Enter integer: 99 Enter double: 3.77 Enter character: z Enter string: Howdy 99 3.77 z Howdy Howdy z 3.77 99 3.77 cast to an integer is 3 mport java.util.Scanner; public class BasicInput {public static void main(String[] args) {Scanner scnr = new Scanner(System.in);int userInt = 0;double userDouble = 0.0;// FIXME Define char and string variables similarlySystem.out.println("Enter integer: ");userInt = scnr.nextInt();// FIXME (1): Finish reading other items into variables, then output the four values on a single line separated by a space// FIXME (2): Output the four values in reverse// FIXME (3): Cast the double to an integer, and output that integerreturn;}}class Lab4Q1P3 { public static void main(String args[]) { int max = 10;while (max < 10) {System.out.println("count down: " + max);max--;}}} Do you know what is wrong with the program? I know that there is error on the 7th line but I don't know what to fix.
- Language: Java Write a program that reads a sentence from the keyboard. Depending on the last character of the sentence, print the message identifying the sentence as declarative (ends with a period), interrogative (ends with a question mark), exclamatory (end with an exclamation point), or other. Hint: you can use charAt() method from the String class to extract the last character of the input line. The character of a String str is at str.length()-1 position. For taking a sentence as input use the nextLine() method from the Scanner class. You have to use if/else if selection. Sample input and output: Sample 1 Input: How are you? Output: Interrogative Sample 2 Input: I am good. Output: Declarative Sample 3 Input: That is amazing! Output: Exclamatory Sample 4 Input: Although, Output: Other Answer:Print "userNum1 is negative." if userNum1 is less than 0. End with newline. Assign userNum2 with 4 if userNum2 is greater than 9. Otherwise, print "userNum2 is less than or equal to 9.". End with newline. 1 import java.util.Scanner; 2 public class UserNums { public static void main (String [] args) { int userNum1; int userNum2; 4 6. 7 Scanner input userNum1 = 8. = new Scanner(System.in); input.nextInt(); input.nextInt(); 9. 10 userNum2 11 12 V* Your code goes here */ 13 System.out.println("userNum2 is " } 14 + userNum2); 15 16 17 }Write an application that counts by five from 5 through 500 inclusive, and that starts a new line after every multiple of 50 (50, 100, 150, and so on). public class CountByFives { public static void main (String args[]) { // Write your code here } }
- Print the two strings, firstString and secondString, in alphabetical order. Assume the strings are lowercase. End with newline. Sample output: capes rabbits 1 import java.util.Scanner; 2 3 public class OrderStrings { public static void main (String [] args) { Scanner scnr = new Scanner(System.in); String firstString; String secondString; 4 6 7 8 firstString secondString scnr.next(); scnr.next(); 9. 10 11 12 /* Your solution goes here */ 13 14 } 15 }This is the question - Write an application that accepts any number of String values from a user until they enter zzz or have entered 15 strings, and display them in ascending order. This is the code I have but it is wrong becuase I didn't get a single check right - import java.util.*; public class StringSort2 { public static void main(String[] args) { // Write your code here Scanner sc = new Scanner(System.in); String s = ""; System.out.print(""); ///loop works until string input is zzz or string length is greater than 15 while (true){ String input = sc.nextLine(); if(input.equalsIgnoreCase("zzz") || input.length()>15) break; s=input; } } }// Converts a string to lowercase, and // displays the string's length// as well as a count of letterspublic class DebugSeven4{public static void main(String[] args){String aString = "HELP!! I need to get 37 things DONE today!!";int numLetters = 0.int stringLength = aString.Length();System.out.println("In all lowercase, the sentence is: ");for(int i = 0; i < stringLength; i++){char ch = Character.toTheLowerCase(aString.charAt(i));System.out.print(ch);if(Character.isLetter(ch))numLetters--;}System.out.println();System.out.println("The number of CHARACTERS in the string is " + stringLength);System.out.println(The number of LETTERS is " + numLetters);}}