. What is the test statistic? Round to 3 decimal places. ?v= . What is the p-value? Round to 5 decimal places. p= . Make a decision. O Do not reject the null Reject the null F. What is the conclusion? O There is sufficient evidence to support the claim that different octanes produce different miles per gallon. There is not sufficient evidence to support the claim that different octanes produce different miles per gallon.

Part of an R output relating X (independent variable) and Y (dependent variable) is shown below. This analysis is based on 11 observations. Using what you know about how all of these values are related, fill in the remaining blanks. Round your answers to 4 decimals in Model Summary box. Round your answers to 2 decimals in the ANOVA table and beyond. Model Summary (4 decimal places each) R R-Squared Adj. R-Squared Pred. R-Squared Source Regression Residual Total ANOVA (2 decimal places each, where necessary) Sum of Squares X Model (Intercept) 0.3632 0.515 1000 RMSE Parameter Estimates (2 decimal places each) Beta Coef. Var. df 29.48 5.7871 Std. Error Std. Beta 0.699 Mean Square -0.72 t F Sig. 3.79 0.0043 -3.091 0.0129 Sig 0.0129

A researcher wants to know whether athletic women are more flexible than non - athletic women. For this experiment, a woman who exercised vigorously at least four times per week was considered "athletic". Flexibility is measured in inches on a sit & reach box. A researcher tested his claim using the following summary statistics: Athletic women Non-athletic women n = 50 * = 5.0 inches s=1.4 inches Assume that all conditions for testing have been met. t = 1.626; p = 0.057 ; At the 1% significance level, state your decision regarding the null hypothesis and your conclusion about the original claim. n = 30 * = 4.6 inches s= 0.8 inches O A. Fail to reject the null hypothesis; there is not strong enough evidence to suggest that athletic women are more flexible, on average, than non-athletic women. O B. Reject the null hypothesis; there is strong evidence to suggest that non-athletic women are more flexible, on average, than athletic women. OC. Fail to reject the null hypothesis; there is…

Need the H0 and H1 values. Can use != for not equal to.

A knewton.com Question The following data was calculated during a study on customer experience. Use the following information to find the test statistic and p-value at a 10% level of significance: • The claim is that the percent of companies that view customer experience as the most vital component of a growing business is different than 50%. Sample size = 50 companies • Sample proportion = 0.40 Use the table or the curve below to find the test statistic and p-value. For the curve select the appropriate test by dragging the blue point to a right-, left- or two-tailed diagram, then set the sliders. Use the purple slider to set the significance level. Use the black sliders to set the information from the study described above. z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 |-1.5 0.067 0.0660.064 0.063 0.062 0.061 0.059 o.058 0.057 0.056 -1.40.081 0.0790.078 0.076 0.075 0.074 0.072 0.071 0.069 0.068 |-1.3 0.097 0.095 0.093 0.092 0.090 0.089 0.087 0.085 0.084 0.082 -1.2 0.115…

A physician wants to copmaure the blood pressures of six patients before and after treatment with a drug. The blood pressures are as follows:  The physician wants to test if there is a significant change of the clood pressure before and after the drug at 0.05 level of significance. the absolute value of the test statistic and the absolute value of the test are, respectively: A. 0.7192 and 1.812 B. 0.7192 and 2.228  C. 1.6151 and 2.015  D. 1.6151 and 2.571

Please solve for G, H, and I.

For c is the null hypothesis rejected?

Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and the sample size. Round the answer to the nearest thousandth where appropriate. mu equals34 ​, sigma equals10​, nequals 17

Note: This is a question that was previously posted and answered, but due to policy only the first three was answered. I have posted the same question below, and have put which parts were answered, and which parts that I still need answered. Thank you. A. ( was answered) B.(was answered) The test​ statistic, t, =-1.74   C. (was answered)The​ P-value is 0.043 D. (was answered) State the conclusion for the test. Reject H0. or Fail to reject H0.   E. Construct a confidence interval suitable for testing the claim that students taking nonproctored tests get a higher mean score than those taking proctored tests. ___<μ1−μ2<___   F. Does the confidence interval support the conclusion of the​ test? (Yes/ No) because the confidence interval contains (zero/ only positive value/ only negative values).