. Utilizing Laplace transforms and matrix-vector formulation, solve the initial value problem yi = -2y2 + 5 sin t · u(t – 2T), y2 = -2y, with y,(0) = 0 and y2(0) = 1. The following partial fraction expansion might be useful in finding inverse Laplace transforms. As + B Cs + D – a² ' s² + w² 1 %3D (s² – a²)(s² + w²) ¯ s² where the coefficients A, B, C and D can be easily determined by considering s | = jw.

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. Utilizing Laplace transforms and matrix-vector formulation, solve the initial value problem
yi = -2y2 + 5 sin t · u(t – 2T), y2 = -2y, with y,(0) = 0 and y2(0) = 1.
The following partial fraction expansion might be useful in finding inverse Laplace transforms.
As + B
Cs + D
– a² ' s² + w²
1
%3D
(s² – a²)(s² + w²) ¯ s²
where the coefficients A, B, C and D can be easily determined by considering s
= jw.
Transcribed Image Text:. Utilizing Laplace transforms and matrix-vector formulation, solve the initial value problem yi = -2y2 + 5 sin t · u(t – 2T), y2 = -2y, with y,(0) = 0 and y2(0) = 1. The following partial fraction expansion might be useful in finding inverse Laplace transforms. As + B Cs + D – a² ' s² + w² 1 %3D (s² – a²)(s² + w²) ¯ s² where the coefficients A, B, C and D can be easily determined by considering s = jw.
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