Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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- The figure displays two circuits with a charged capacitor that is to be discharged through a resistor when a switch is closed. In figure (a) below, R₁ = 23.32 and C₁ = 5.04 μF. In figure (b) below, R2 = 10.82 and C₂ = 8.10 μF. The ratio of the initial charges on the two capacitors is 902/901 = 1.61. At time t = 0, both switches are closed. At what time t do the two capacitors have the same charge? 0.0 (a) (b) Number i Unitsarrow_forward1) Propose and draw a circuit of a resistive current divider in halfarrow_forwardPlease answer in typing format solution Sir please help Thanks in advancearrow_forward
- In the diagram below, the switch S has been closed for a long time. A) What is the output voltage Vout? What is the charge on the capacitor? b) The switch is opened, so the output voltage increases. What is the time constant that describes the charging of the capacitor in terms of R and C? c) When Vout reaches 10 V, the switch closes and the capacitor begins to discharge. What is the time constant that describes the discharging in terms of R and C? Hint: Apply Kirchhoff's Rules to both loops and the sum of the currents at the junction above the capacitor in the diagram, and use I=dq/dt. If the switch opens when Vout reaches a lower value, say 5V, the capacitor will charge again, and thus one can cycle the voltage with a time constant determined by the circuit: this demonstrates the principle of operation of an electronic timer. 4R S 15 V Vout Rarrow_forwardFind the Equivalent Capacitance between P and Q from the figure belowarrow_forwardExplain the inductor equation and what is going on?arrow_forward
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