. Consider a resistor network connected to a 32.0-V battery as shown. The battery has negligible internal resistance. If the equivalent resistance of the resistor network is 6.40 Q, what is the value of the resistance of one of the resistors? a) 0.562 Q b) 5.50 2 c) 2.50 2 d) 1.10 Q E = 32.0 V 2.00 N 2.00 N 1.50 N R 3.00 N 3.00 N . From the circuit network in Item 7, what is the potential difference across the resistor ? a) 4.50 V b) 7.50 V c) 5.00 V d) 12.5 V . Consider the circuit as shown in the diagram. Using the current directions set in the diagram, what are the values for I,1, and I3? a) I1 = 2.17A, I2 4.00A, I3 = %3D 1.83A b) I1 = 1.50A, I, 0.500A 2.00A, I3 = || %3D R, = 82 c) I1 = 0.346A, I2 = 3.45A, I3 = 3.19A EV2 = 10 V EV, = 24 V R2 = 62 d) I = 4.50A, I2 = -2.00A, I3 = = 4 2 -6.50A 12

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Chapter10: Direct-current Circuits
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< How R you? Part 1>. Consider a resistor network connected to a 32.0-V battery as shown. The
battery has negligible internal resistance. If the equivalent resistance of the resistor network is
6.40 Q, what is the value of the resistance of one of the resistors?
a) 0.562 Q
b) 5.50 2
c) 2.50 2
d) 1.10 2
Ɛ = 32.0 V
2.00 N
2.00 N
1.50 N
R
3.00 N
3.00 N
<How R you? Part 2>. From the circuit network in Item 7, what is the potential difference across
the resistor ?
a) 4.50 V
b) 7.50 V
c) 5.00 V
d) 12.5 V
<Triplel>. Consider the circuit as shown in the diagram. Using the current directions set in the
diagram, what are the values for I1, 12, and I3?
a) 1 = 2.17A, I2 = 4.00A, I3 =
1.83A
2.00A, I3 =
b) l1
1.50A, I2
0.500A
R 82
:V2 = 10 V
c) 1 = 0.346A, I2 = 3.45A, I3 =
3.19A
:V = 24 V
d) I = 4.50A, I2 = -2.00A, I3 =
R2 =
62
R3 = 4 2
-6.50A
12
Transcribed Image Text:< How R you? Part 1>. Consider a resistor network connected to a 32.0-V battery as shown. The battery has negligible internal resistance. If the equivalent resistance of the resistor network is 6.40 Q, what is the value of the resistance of one of the resistors? a) 0.562 Q b) 5.50 2 c) 2.50 2 d) 1.10 2 Ɛ = 32.0 V 2.00 N 2.00 N 1.50 N R 3.00 N 3.00 N <How R you? Part 2>. From the circuit network in Item 7, what is the potential difference across the resistor ? a) 4.50 V b) 7.50 V c) 5.00 V d) 12.5 V <Triplel>. Consider the circuit as shown in the diagram. Using the current directions set in the diagram, what are the values for I1, 12, and I3? a) 1 = 2.17A, I2 = 4.00A, I3 = 1.83A 2.00A, I3 = b) l1 1.50A, I2 0.500A R 82 :V2 = 10 V c) 1 = 0.346A, I2 = 3.45A, I3 = 3.19A :V = 24 V d) I = 4.50A, I2 = -2.00A, I3 = R2 = 62 R3 = 4 2 -6.50A 12
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