Concept explainers
1. Assume that a camera has a bi-convex lens. Should you move the lens toward or
away from the sensor in order to zoom in (magnify)?
2. A camera has a bi-convex lens whose focal length is 50mm. The lens’s range of
motion is 5.56mm starting from 50mm from the sensor and moving away. What
are the minimum and maximum possible object positions for which the image is in
focus?
3. For the camera in the previous question, when a 300mm tall object is at the minimum
distance, will it fit on a Canon APS-C sensor? Hint: Look up the size of this camera
sensor.
4. See Figure 10.7! A circular piece of glass (n=1.5) has been cut in half as shown
and is being used as a lens for a set of five parallel rays. The angles at which
the rays are incident on the circular side of the lens are shown, and the image is
drawn to scale. First, calculate the 5 angles of refraction for each of the 5 angles
of incidence, respectively. Second, use a protractor to draw the refracted rays such
that they intersect the dashed line. Finally, comment on whether a circular piece of
glass makes a good lens or not.
5. Based on the drawing and calculations you did in Question 4, how would the focal
length of a lens change if it was submerged in water (n=1.33)?
Step by stepSolved in 4 steps with 3 images
- An object is 50 cm to the left of a +20 cm focal length lens. Where does the image form? O a. 20 cm to the right of the lens b. At infinity c. 50 cm to the right of the lens O d. 33 cm to the right of the lensarrow_forwardAn object is placed 30.0cm to the left of lens A. Lens B is placed 40.0cm to the right of lens A. Lens A is converging and has a focal length of 20.0cm . Lens B is diverging and has a focal length of −30.0cm . a. What is the final image position relative to lens B? (Include the + or – sign.) b. What is the overall magnification? (Include the + or – sign.) c. Is the final image real or virtual? d. Is the final image upright or inverted?arrow_forwardWhich of the following statements for single optic devices are true? Choose all that apply. a. Any physicist worth their weight in garbanzo beans (not chick peas) knows that concave lenses will have a positive focal length. b. For virtual images, the image distance is positive and the object distance is negative. c. By convention, if the image height is positive then the image is upright. d. If an optic produces an image with a magnification of 0.6, then the image is diminished. e. Experiments have shown that convex mirrors can create real images. f. If an image has a magnification of -6, then the image is real.arrow_forward
- An object is 8.5 cm away from a thin convex lens with focal length of f1 = 3.1 cm. 8.0 cm away from the first convex lens is a second convex lens on the same optical axis with focal length of f2 = 2.1 cm. a) Draw a principal ray diagram for the optical system including the different focal lengths, image and object distances. b) Describe the nature (real or virtual) and orientation of the final image relative to the object. c) Calculate the position of the final image after the two lenses and its magnification.arrow_forwardThe diagram shows 2 out of the 3 possible principal rays traversing a thin lens of unknown type. The focal points are labeled F1 and F2, the object is at 0, and the image is at I. Which of the following statements are true? Select one or more: O a. This is a divergent lens. Ob. This is a convergent lens. Oc. The magnification is about-2 Od. The magnification is about 2. De. The image is virtual. Of The image is realarrow_forwardAn object is placed 45.0cm to the left of lens A. Lens B is placed 40.0cm to the right of lens A. Lens A is converging and has a focal length of 20.0cm . Lens B is converging and has a focal length of 10.0cm . a. What is the final image position relative to lens B? (Include the + or – sign.) b. What is the overall magnification? (Include the + or – sign.) c. Is the final image real or virtual? d. Is the final image upright or inverted?arrow_forward
- Create a ray diagram for eyeglasses that contain a diverging lens. Assume you are looking at a 2 cm tall object that is 4 cm from the lens. The focal length is 3 cm. What type of vision are they used to correct? Give both names. How do they do this? Explain.arrow_forwardAnne's retina is 1.8 cm from the lens. The nearest object she can see clearly without corrective lenses is 2.0 m away. 1. Sketch a ray diagram to show (qualitatively) what happens when she tries to look at something closer than 2.0 m without corrective lenses. 2. What should the focal length of her contact lenses be so that she can see clearly objects as close as 20.0 cm from her eye?arrow_forward3. In order to see an upright and magnified virtual image using a converging (positive) lens with a focal length of f, the object distance (d) must be: A. 0arrow_forwardarrow_back_iosarrow_forward_ios
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