. A deadlock avoidance algorithm dynamically examines the __________ to ensure that a circular wait condition can never exist. a) resource allocation state b) system storage state c) operating system
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3. A deadlock avoidance
a) resource allocation state
b) system storage state
c)
d) resources
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- 7. When several processes access the same data concurrently and the outcome of the execution depends on the particular order in which the access takes place is called ________ i) dynamic condition ii) race condition iii) essential condition iv) critical conditionProcess Scheduling: Select all statements below that are true Dynamic Priority Round Robin (DPRR) makes use of a preliminary stage containing prioritized queues. When Multilevel feedback (MLF) scheduling is applied, processes at lower priority levels can take more processor time than processes at higher levels. Multilevel Priority (ML) scheduling is based on priority queues and uses a fixed set of priorities. When Multilevel Feedback (MLF) scheduling is applied, processes do not remain at the same priority level, but gradually migrate to lower levels each time they use up their allotted time threshold. Priority Inversion means that low-priority processes can be delayed or blocked by higher-priority processes.Real Time Scheduling: Select all statements below that are true EDF scheduling assigns the highest priority to a process with the smallest remaining time until its deadline. RM scheduling assigns a higher priority to processes with shorter periods. Rate Monotonic (RM) scheduling works by dividing the total amount of time available into an equal number of shares, and then each process must request a certain share of the total when it tries to start. If a process has period p, it is activated every p units of time. A real-time system is schedulable under Earliest Deadline First (EDF) when its overall CPU utilization is less than or equal to 1. A real-time system is schedulable under RM when its overall CPU utilization is less than 1.
- Assignment description: When an operating system has been running for a while without reboot, and more it keeps allocating and de- allocating pages, the quicker the memory becomes fragmented. And the kernel may not always be able to defragment enough memory for a requested size on time. If that happens, applications may not be able to allocate larger contiguous chunks of memory even though there is enough free memory available. Being a system admin and considering the following scenario, discuss the current proposed solutions to solve the problem caused in this case and critically analyze the performance of the proposed solutions to solve the problem. Provide a report considering the following outlines. Scenario: In the following snapshot of running operating system, we can see that there is a free memory space equal to (55 KB). Assume that new process (process#07) needs to be run inside the memory and required 50 KB but the memory (fragment) is not contiguous. Assigned Space Assigned…Computer Science An automobile service company needs an AUTOMOBILE SERVICE BOOKING SYSTEM (ASBS) to enable its customers to schedule their car service bookings on a particular date and time. ASBS should accommodate 2 type of users namely Admin and Customer. Each of these users will be required to perform the following functionalities: Functionalities of Admin i. Login to Access System ii. Maintain Available Booking Slots a. Add Available Booking Slots b. Delete Available Booking Slots iii. Display a. Available Booking Slots on a particular date* b. Booked Slots on a particular date c. Booking details of all customers on a particular date (this includes booking slots, customer name, contact number and car registration number) iv. Search all booking records for a particular Customer v. Exit the system How to do pseudocode and flowchart for the question above?How unlike are the concepts of "preemptive" and "preemptive scheduling"?
- Operating system is a resource allocator so a. It provides system call to abstract the access to the different resources b. It prevents an unprivileged process from accessing a memory location related to another process c. it provides a command line interface that helps to access the system resources d. It controls the CPU time sharing among the processes in the ready queue26. The Little Man Computer Calculator Mailboxes In Basket Out Basket Instruction Little man Reset button location counter He's Back! Your task is to design an operating system for the Little Man Computer so that several programs can run concurrently. How would you modify the above diagram for this to occur? You will be graded on using operating systems principles and you should cover such concepts as concurrency, state saving, time slicing, and priority.Critical Sections - Select all of the following statements that are true A critical section is a segment of code in which a process has write-access to data or resources that are shared with at least one other process. Every process waiting to enter a critical section must be allowed to enter it at some point. No eternal waiting must be possible. In a system consisting of n processes, a critical section protected by a mutex variable can be accessed by more than one process at a time. A process not executing in a critical section must not prevent other processes from entering the critical section. Critical sections must never contain data shared by multiple processes. O DELL W
- Question Completion Status: QUESTION 25 A(n) refers to where a process is accessing/updating shared data. OA) critical section OB) entry section OC) mutex OD) test-and-set QUESTION 26 Which of the following is true of cooperative scheduling? OA) It requires a timer. OB) A process keeps the CPU until it releases the CPU, either by terminating, or by switching to the waiting state. OC) It incurs a cost associated with access to shared data. OD) A process switches from the running state to the ready state when an interrupt occurs. Click Save and Submit to save and submit. Click Save All Answers to save all answers. Q SearchCPU Scheduling: Answer the following questions with a brief paragraph for each: 1) What is non-premptive? 2) What is preemptive? 3) What is preemptive with concurrency?46. An operating system contains 3 user processes each requiring 2 units of resource R .The minimum number of units of R such that no deadlocks will ever arise is a. 4 b. 3 c. 5 d. 6