Calculate the Period of a Wave That Has a Wavelength of 5 Meters and Travels with a Speed of 7 Meters per Second in a Medium.
Answer – The period of a wave can be found using a modified version of the wave equation, T . For the given wave, it is found to be 0.714 s.
Explanation:
To know how to find the period of a wave, we need to review what it is with its related terms.
The period of a wave, indicated by T, is the duration of a complete wave cycle. Its frequency (f) is the number of cycles the wave completes in one second. Thus, frequency is the inverse of the period of a wave and vice versa.
So the formula for the frequency of a wave is:
f = 1 T
And the formula for the time period of a wave is:
T = 1 f
Further, the distance that a wave moves in one period is known as its wavelength, represented by λ .
Since the given question provides us with the values of wavelength and speed, we can use all the above information with respect to a wave in the equation Speed (v) = Distance / Time:
v = λ T
v = λ × 1 T
v = λ × f
v = f λ
This is the wave equation, which represents the relationship between the speed of a wave, its frequency, and its wavelength.
Since the given question requires us to find the period of the given wave, the wave equation can be modified as follows:
v = λ T
T = λ v
Substituting λ = 5 m and v = 7 m/s from the question in the above equation, we get:
T = 5 m 7 m / s
T = 0 . 714 s
Popular Questions
Two dimensional dynamics often involves solving for two unknown quantities in two separate equations describing the total force. The block has a mass m=10kg and is being pulled by a force F on a table with coefficient of static friction μs=0.3. Four forces act on it: The applied force F (directed θ=30∘ above the horizontal). The force of gravity Fg=mg (directly down, where g=9.8m/s2). The normal force N (directly up). The force of static friction fs (directly left, opposing any potential motion). If we want to find the size of the force necessary to just barely overcome static friction (in which case fs=μsN), we use the condition that the sum of the forces in both directions must be 0. Using some basic trigonometry, we can write this condition out for the forces in both the horizontal and vertical directions, respectively, as: Fcosθ−μsN=0 Fsinθ+N−mg=0. In order to find the magnitude of force F, we have to solve a system of two equations with both F and the normal force N unknown. Use the methods we have learned to find an expression for F in terms of m, g, θ, and μs (no N). find the magnitude of the force F (in kg⋅m/s2) necessary to make the block move.
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