Find the Length and Width of a Rectangle, Given That the Length is 4 Times the Width and the Perimeter is 60 Inches.
Answer – The length of the given rectangle is 24 inches, while its width is 6 inches.
Explanation:
Let us assume that l is the length of the rectangle and w is its width.
Since the length is given to be 4 times the width, l=4w.
Further, the perimeter of the rectangle, which is 60 inches here, equals the sum of all its sides.
So we can set up an equation for the perimeter, substitute all known values, and then solve for the width as follows:
Perimeter = Length + Width + Length + Width
60 = l + w + l + w
60 = 4 w + w + 4w + w
60 = 10w
w = 60 / 10 = 6
So the width of the rectangle is 6 inches.
Using this value, we can calculate the length by substituting the value of the width in the equation l = 4w:
l = 4(6)
l = 24
Thus, the length and width of the given rectangle are found to be 24 inches and 6 inches, respectively.
