Sample Standard Deviations

There were three different runs in order to have comparable data and to increase the validity of the experiment. The first run gave 39% of Sodium Bicarbonate. The second run gave 34% of Sodium Bicarbonate while the third one gave 39%, which is the same as the first run. The average percentage was 37% which is much lower than the manufacturer's percentage of 59%. The percent error came out to be -37%.

Eighty percent of those who play the state lottery never win more than $100 in one play. A sample of 500 players was drawn and the mean winning was $125. One Sample Z-Test

The average number of breakdowns from the simulation trials was 1.93 with a standard deviation of 0.20. No. of breakdowns per week

(b) The value of Z with an area of 5% in the right tail, but not the sample mean.

Hence, variance of 3 weeks is equal to the Sum variance of per week that is, 25+100+225=350 Standard Deviation of 3 weeks is equal to the Square root of the variance of 3 weeks that is, Square root of 350 = 18.71. Now that we have the found the mean and standard deviation of 3 weeks, let’s find ' z ' value by using the formula:-Z = ( total value - total mean ) / standard deviation that is,Z = 180-160/18.71 = 1.07.

Read the directions and write answers independently. 1. (L.2) Choose the sentence with correct capitalization and punctuation. A. Mrs. Brown catches the bus at the corner of Elm and N. Grove.

8. Analyze: How does the standard deviation relate to the consistency and range of a data set?

Sport Obermeyer Sport Obermeyer started to make firm commitments for producing its 1993-1994 line of fashion skiwear with scant information about how the market would react to the line. Inaccurate forecasts of retailer demand had become a growing problem at Obermeyer: in recent years greater product variety and more intense competition had made accurate predictions increasingly difficult. Also, another issue Sport Obermeyer faced was how to allocate production between factories in Hong Kong and China. They need consider all aspects in a short-term period and also a long-term period. Questions: 1.

Sue has 10 pictures but only has space in her apartment to hang 4 of them on a wall. The number of different arrangements of four pictures from a selection of ten pictures is:

The average of 17 results is 60. If the average of first 9 results is 57 and that of the last 9 results is 65, then what will be the value of 9th result?

This test was used in order to determine if there were too many or too few runs in a series of data. After conducting the runs test it produced a z-value of -5.9123, which indicates the amount of standard errors of the identified number of runs below the expected number of runs. The p-value indicates how extreme the z value is and with a p-value (0.0001) which is less than .05 or .1 the null hypothesis of randomness is rejected (Figure 1).

2) Compute the standard deviation for each of the four samples. Does the assumption of .21 for the population standard deviation appear reasonable?

5) From calculations, computed z value is more than -1.65 and falls within Ho not rejected region. Ho is not rejected at α = 0.05 & α = 0.01 significance levels.

After using the sample of 200 students in the BS program at Whatsamatta U. I conducted a hypothesis test using Analysis of Variance to determine if there is a difference in the mean GPA, for those who are unemployed vs. working part time vs. working full time. When conducting this test I will use a significance level of .05. After loading the data the summary table reveals that the average GPA of students who are unemployed is 3.388. The average of the students who work part time is 3.49. And the average GPA of the students who work full time is 3.563. After loading my data, I discovered that not all of my means are equal in the 3 quiz format. With a p-value of 0.130, I will reject the null hypothesis. Since my probability value is within my

Behavior commonly seen in children that is the result of some obstacle to normal development such behavior may be commonly understand as negative (a timid child, a destructive child) or positive (a quite child), both positive and negative deviation will disappear once the child begins to concentrate on a piece of work freely chosen by him.