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Lab Report Essay

Decent Essays

The purpose of this report is to confirm the lithology and porosity of the reservoir for my company, which is considering a water flood on a reservoir overlain by a shale seal. Also to investigate the mechanical properties of the shale seal. ∅=(∆t-∆t_ma)/(∆t_f-∆t_ma ) ………………..……......……………(1) Firstly, the saltwater neutron-density cross plot from the Schlumberger chart book was used to find the porosity and lithology of the reservoir. Figure 1 shows the usage of the neutron-density cross plot and by that the porosity was found to be 17% and the lithology was read to be quartz sandstone. Then Eq. 1 was used to calculate the sonic porosity with substituting ∆t with 78 μsec/ft, ∆t_ma with 55.5 μsec/ft, which is for sandstone and ∆t_f with 185 μsec/ft that is for saltwater based mud. Then, the sonic porosity was obtained to be 17.37%. The sonic porosity for the reservoir is so close and does agree with the neutron-density porosity, which was found to be 17%. v=(1/2 ((∆t_s)/(∆t_c ))^2-1)/(((∆t_s)/(∆t_c ))^2-1) ……………..……......……………(2) μ=ρ/(∆t_s^2 )*〖13400*10〗^6………..……......……………(3) E=2μ(1+v) …………..……......……………(4) Afterwards, the correct Poisson’s ratio was found. This was calculated using Eq. 2 by plugging ∆t_swith 155 μsec/ft and ∆t_c with 85 μsec/ft which were given in the assignment. So, the correct …show more content…

5. This was found easily by substituting the correct Poisson’s ratio that was found previously and equal to 0.285. The pore pressure gradient of 0.46 psi/ft and an overburden gradient of 1.00 psi/ft, those two numbers were multiplied by the provided midpoint depth of 6200 ft to give the P_o and P_r which were used in Eq. 5 to find the fracture pressure. Also, with substituting α with 0.5, the fracture pressure was calculated to be 5231.286 psi. This impose a restriction on the water flood job so, to avoid fractures, it is necessary to maintain water-flooding operations below the fracturing

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