Chem 2200 Date:March 13th, 2016 Lab 6: Synthesis and Analysis of [1,3,5-C6H3(CH3)3]Mo(CO)3 Abstract: The purpose of this experiment is to use the apparatus shown in figure 7-1 of experiment 6 found in the lab manual, to synthesize [1,3,5-C6H3(CH3)3]Mo(CO)3.(2016 Oleg) With this, characterization of the molecule can be accomplished using the infrared spectrum and NMR spectrum of the synthesized compound. It was found in the IR spectra of the product, that suitable stretches were found associated with the C-O bonds of mestylene and molybdenum. With One strong spectra was found at 1855.3973 cm-1 , one medium strength spectra was found at 1942.6002 cm-1 , and one weak spectra of C-O stretch was found at 1298.8638cm-1 . The 1H NMR spectrum of the product showed peaks at δ 2.28 and 5.25, while the H NMR spectrum of mesitylene gave peaks at δ …show more content…
Benzene and its derivatives have been found to replace donor ligands. In this experiment one is looking to replace the CO groups in a molybdenum complex. By refluxing the Mo(CO6) in mestylene it is possible to produce 1,3,5-C6H3(CH3)3]Mo(CO)3. The benzene molecules replace 3 of the CO bonds and rest parallel to the plane of the remaining CO groups. The products geometry is such that it can be considered octahedral as opposed to tetrahedral. The carbonyl to molybdenum bonds are close to 90 degrees instead of 109.5 which is indicative of a tetrahedral complex. Using H NMR and infrared spectrum it is possible to analyze the product and determine its relative structure and composition. CO stretches have unique places within the spectrum and thus can be noted. H NMR can be used to determining the structure by comparing it to that of mestylene. Looking at these spectrum’s allows for one to look for indication of methyl group
This lab could have contained errors. The errors could have happened when performing the lab. Some of the possible errors in this lab are:
2. Using the atom and bond library below, construct the following molecule. It may be
Organometallic compounds, such as Grignard reagents, are molecules containing carbon-metal bonds and are often used to create new carbon-carbon bonds. Grignard reagents—or organomagnesims— are specifically those that have a carbon-magnesium bond.
The purpose of this experiment was to synthesize the Grignard reagent, phenyl magnesium bromide, and then use the manufactured Grignard reagent to synthesize the alcohol, triphenylmethanol, by reacting with benzophenone and protonation by H3O+. The triphenylmethanol was purified by recrystallization. The melting point, Infrared Spectroscopy, 13C NMR, and 1H NMR were used to characterize and confirm the recrystallized substance was triphenylmethanol.
8. ISBN: 0-558-05245-2 Virtual ChemLab: General Chemistry, Student Lab Manual/Workbook, V. 2.5, Third Edition, by Brian F. Woodfield and
After putting the CH2Cl2 to a beaker containing the drying agent anhydrous sodium sulfate, a sticky white solid was recovered.
Through the use of the Grignard reaction, a carbon-carbon bond was formed, thereby resulting in the formation of triphenylmethanol from phenyl magnesium bromide and benzophenone. A recrystallization was performed to purify the Grignard product by dissolving the product in methanol. From here, a melting point range of 147.0 °C to 150.8 °C was obtained. The purified product yielded an IR spectrum with major peaks of 3471.82 cm-1, 3060.90 cm-1, 1597.38 cm-1, and 1489.64 cm-1, which helped to testify whether the identity of the product matched the expected triphenylmethanol. The identity of the product being correct was further confirmed by way of both proton and carbon-13 NMR spectra. This is due to the fact
The purpose of this lab was to synthesize triphenylmethanol from benzophenone and bromobenzene by the formation of a Grignard compound with the reagents bromobenzene and magnesium metal. The bromobenzene was first transformed into the Grignard compound and was then reacted with the benzophenone to make the final product. The mixture was then mixed with sulfuric acid and the organic layer was extracted via a separatory funnel. The mixture was then recrystallized from methanol and was allowed to dry and the percent yield, melting point, and the IR was obtained. The mass of the product obtained was 5.45 grams and the percentage yield was determined to be 41.95%. The melting point range obtained from the final product was 89-91°C
Timberlake, K. C. (01/2014). Chemistry: An Introduction to General, Organic, and Biological Chemistry, 12th Edition.
The final product formed was characterized by using an infrared spectroscopy and chemical reaction. The IR spectrum was expected to show a carbon double bond (alkene) and many C-H sp³ hybridization bonds (alkyl) from the final product. This was compared to the authentic sample with its vibrational bonds. Once done identifying how close the sample is with the authentic sample, that would be the evidence to support the product’s
Once in the program Element and C was selected under the Builder Window, then center of the View1: New window was clicked to make a CH4 molecule appear.
For the identification of the product, IR, 13C NMR and 1H NMR spectra were examined, and the product was found to be butyl propionate. In the IR spectrum, RM-11-Bi, five key peaks are observed. These peaks are sp3 hybridized carbons at 2961 cm-1 and 2877 cm-1, an ester at 1737 cm-1, a
The bond in this molecule is a covalent bond. This molecule is nonpolar. The structure of this molecule involves London dispersion forces (LDF).CO2: The electronegativity value between the atoms of this molecule is 1.0. The bond in this molecule is a covalent bond. This
The M-C3 and C1- C2 single bonds are broken to form a metal alkylidene and ethylene.
Molybdenum is a chemical element with symbol Mo and atomic number 42. The name is from Neo-Latin molybdenum, from Ancient Greek Μόλυβδος molybdos, meaning lead, since its ores were confused with lead ores. The mass number is 95.94, number of neutrons is 54, the electron configuration is [Kr]4d⁵5s¹.