Elastic and Inelastic Lab
By. Spencer Schibig
December 10th, 2015
Elastic and Inelastic Lab
By. Spencer Schibig
December 10th, 2015
Introduction Do elastic and inelastic collisions obey the conservation of momentum principle?The law of momentum conservation principle means a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision. That is, the momentum lost by object 1 is equal to the momentum gained by object 2. It is important, because this experiment we can see momentum conserved in a collision and seeing if the collision is elastic if it bounces of each other or if it is inelastic
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Run a inelastic collision by pushing one cart with the velcro on it from the the edge of the ramp into the other cart in the center of the ramp and record velocity of lab-quest.
Repeat steps 3-6 with a 500g weight on the cart colliding into the other cart.
Results
Control= .71 m/s
Table 1- Elastic Collision
Run
D1 (m/s)
D2 (m/s)
1
.70
.69
2
.76
.74
3
.69
.69
4
.53
.53
5
.75
.75
Table 1 we see that the numbers are relatively the same, because the law of conservation momentum principle the total momentum before the collision equals the total momentum after and we see this in the data.
Table 2 - Inelastic Collision
Run
D1 (m/s)
D2 (m/s)
1
.71
.37
2
.71
.37
3
.74
.39
4
.72
.37
5
.68
.35
Table 2 we see the numbers are halved and that is because when the carts stick together the mass is doubled and causes the velocity to decrease by half.
Table 3 - Elastic Collision WIth 500g Weight
Run
D1 (m/s)
D2 (m/s)
1
.64
.37
2
.66
.37
3
.66
.32
4
.70
.37
5
.71
.37
Table 3 we see the D2 halved, because the weight is doubled with the 500g weight making the momentum to allow only half to go with the second cart after they
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We had some error in our experiment, with human error launching the cart and we did not record the carts bouncing back from the wall. Our data is consistent and we can observe the difference between each table. We were able to see the cart’s total momentum equal around the same after the collision, unless it was an inelastic collision or if we added the 500g the velocity would be halved.The max force that occurs during a collision is a function of the change in velocity over a change of time. The shorter the time span, the larger the force must be. However it did not change the momentum, because the according the law of conservation momentum principle the energy is conserved within the system. If we would have recorded D3 when the cart bounced off the wall after collision we would have an even more accurate account of the law of conservation momentum
From the first test, which had the dummies sitting upright, and the data was: 41ft/sec, 54 milisec collision time, and 21g-force exerted on the
Example: A 1500kg car traveling at 100km/h (27.7ms-1) hits a wall and stops to 0ms-1 has an impulse of 41,550kgms-1. An older 2000kg car traveling at the same speed also hits a wall and stops to 0ms-1 with an impulse of 55,400kgms-1.
(c) Assuming no sound generated in the impact, all the energy lost will turn into heat energy. The heat energy generated is equal to the difference between the energy before the impact
The ball now has kinetic energy. Kinetic energy like momentum in that it comes from the mass of the object and its velocity. Kinetic energy was transferred from the plunger to the ball just like momentum was but only if the collision was elastic. During and elastic collision kinetic energy is conserved. The balls kinetic energy is half of its momentum squared. This means the balls momentum is its mass multiplied by velocity, and then it is squared and divided by two. If the velocity or speed of the ball is reduced by one half then the overall kinetic energy is reduced by a factor of four (Kirkpatrick and Wheeler p.106)
When mass is added to the propeller car the average speed and acceleration(a vehicle's capacity to gain speed within a short time) begins to decrease because of the amount of gravity and friction acting upon the object. All the iterations done were within 500 centimeters of distance and different amounts of weight were added to the car each trial. The mass increased while the speed decreased. When we had 0 grams placed on our vehicle it traveled at an average of 4.56 seconds, when 50 grams were added to the vehicle it slowed down having a average of 5.57 seconds, on the last trial 100 grams were added on the vehicle it took 5.73 seconds to cross the finish line. The way I graphed those data points was by putting the average time to travel 5m(s)
During the collision in the first test, the dummy on Trolley A propelled forward and off the trolley due to the collision which had caused damage to the dummy and trolley. If it were to happen to occupants of a moving car colliding with a stationary car, the occupants in the car would have a higher chance of getting more damage done to the occupants and the car then it would to the stationary car. As the moving car is colliding to the stationary car, energy from the moving car will be exchanged to the stationary car causing momentum. (Questacon: The National Science and Technology Centre,
a) Click on the reset button. Adjust the glider masses back to 0.5 kg. Reposition the gliders with G1 on the left end of the track, and G2 on the right end, since both gliders will have an initial velocity moving toward each other for the collision. The exact position of each is not important, as long as they can collide near the middle. b) Record the masses of G1 and G2 in Table D. Calculate and record the combined mass of the gliders as well. c) Set the velocities to 3.0 m/s for G1, and –3.0 m/s for G2. Record the initial velocity and momentum of each glider in Table D as well. d) Press play to run the trial. After the collision, press pause to record velocity and momentum data for the combined gliders in Table D. e) Run a second trial. Click the reset button and change the mass of G2 to 0.8, and keep the other parameters the same. Record masses, velocities, and momentums as you did in Steps 3b–c, this time in Table E. Run the simulation, pausing after the collision to record postcollision velocity and momentum of the gliders in Table E. f) Repeat Step 3e to run a third trial where the mass of G2 is increased to 1.2 kg. Record masses, velocities, and momentum both before and after the collision in Table F. Step 4: Compare values for momentum. a) In each Table, find the momentum for each glider prior to the collision and for the combined mass after the collision. Momentum is calculated by using the
In this experiment the egg did not break. When I threw it at the sheet the egg was absorbed and deflected. The egg did not break because it flew into a flexible sheet that was not a hard, flat surfaace. If we look exclusively at the momentum of the egg, we would find that the foward momentum was mostly distubuted into the sheet. Because of the lost of momentum, the egg simply rolled down the sheet, unscathed. Had we thrown the egg (or something that would not break like a baseball) at an elastic trampoline-like suface then the momentum would have been reciprocated in the backwards direction because of the surface’s elastisity. The change in momentum of an object equals the impulse applied to it.
Using the toy cars and track, the lab was conducted to prove that the momentum before a collision would be equal to the momentum after a collision. The most significant results that was produced by the experiment was that the momentum before the collision, being 0.05929 kg*m/s, and the momentum after, being 0.0682 kg*m/s, were not equal like they should have been. These results from the lab were not accurate in the fact that the before and after momentums were not the same, which helps to show that lab measurements will be slightly off due to inaccuracy of the lab equipment.
The collision that conserved the least amount of energy was the explosion. Though you could not calculate the percent error because the initial velocity was zero, but you can blatantly tell that this collision did not conserve energy at all. The energy switched from Ee to Ek, and the actual spring acts as an outside force. Therefore, the energy to start with during the explosion collision is totally different than what it ends with. With reference to energy and momentum conservation, we can see that throughout this whole experiment that one-hundred percent energy and momentum conservation was not possible, the magnetic head-on collision came as close as we can to conservation. Thus, this experiment results as the collisions being inelastic, but the most elastic collision was the magnetic head on collision because energy and momentum were conserved the best through this
The total momentum and total kinetic energy before and after do not match up because the final momentum and kinetic energy is smaller in the straight on collision and larger in the nearly straight on and glancing blow. For kinetic energy to be lost like in the straight on collision means that the kinetic energy was transformed into another type of energy like sound because in real life when the balls collide, a sound can be heard during the collision. However for kinetic energy to be gained does not make sense, meaning something was wrong with the apparatus or calculations. Part of the results do reflect the theory since for the straight on collision, the most of the velocity from the blue ball is transferred to the red ball. And in the nearly straight collision and glancing blow both balls have
The second modification is the propeller. We placed the propeller on are object, because we wanted the collision time to be longer. And how does the propeller makes the collision time longer? Well, the propeller spins around and cause it to “float” and it'll help lift are object a little bit, causing the collision time to last
Step 5: The cup that the marbles roll in comes up and hits a golf ball that is on a tilted side and falls on a meter stick. The golf ball has potential energy sitting on the side. The speed of the cup as to be perfect or we will miss the golf ball. The mass doesn't really matter in this step. There was rolling friction will the golf ball rolling off the edge.
What was the percentage difference between your change in momentum and the impulse for all three conditions (Large Glider w/out clay, Small Glider w/out clay, Small Glider w/ clay)? Were these values within the uncertainties calculated by your error analysis?
HYPOTHESIS: Without the effects of friction the momentum will be conserved in the isolated system. In all three experiments the momentum before the interaction will equal the momentum after the interaction.