Group B

2. I have 20% chance to have cavity gene. If I do have the gene, there is 51% chance that I will have at least one cavity over 1 year. If I don’t have the gene, there is 19% chance that I will have at least one cavity over 1 year. Given that I have a cavity in 6 months, what’s the probability that I have at least a cavity over 1 year?

The cumulative probability of outcomes from 4 to 20 is .6%. The outcome parameters were 4 to 20 because, we were specifically asked to look at the probability of Four-D rejecting >=4 or more shipments in 20 days.

f) To find the probability of each of these answers you would start by dividing the possible successful outcomes by the total number of possible outcomes. In the example E, the question asked for anyone except an administrator, therefore, taking the total amount of people minus the administrator will give you a category for those you want to have picked. After that, you would continue as if you had the successful possibilities divided by all possible

(2) Give that a sample of 25 had x = 75, and (x-x)² = 48 the mean and standard

Find P(12 < x < 23) when mu = 19 and sigma = 6. Write your steps in probability notation.

The worksheet “Insurance” in the Excel workbook MATH302_Midterm.xls, which is attached, contains data on the percentage of people without health insurance coverage. These data are based on samples taken in 2004 for the fifty states and the District of Columbia. Use these data to answer questions 1 through 4.On average, what percentage of the people in the fifty states and the District of Columbia does not have health insurance? Place your answer, rounded to 2 decimal places, in the blank. 14.15 Do not use a percent sign. For example, 17.76 would be a legitimate entry.

distribution with an average of 2 per 30 second period. What is the probability of having

Find P(X > 0). Place your answer, rounded to two decimal places in the blank. For example, 0.56 would be a legitimate entry. 0.45

24) The cumulative probability for all six outcomes of tossing a fair die should end with the value 1.00.

A random sample over the course of a few weeks produces 91 surveys or customer complaint cards. The observations produced a mean of x= 26.1 and a standard deviation to s= 2.8. Since the sample size is large the standard formula will be used. The equation will be 26.1 + and – 1.960 2.8 / the square root of 91. Once the calculations are done we can determine the calculations will be 26.1 + and – 0.58. Thus the 95% confidence level for u will be 25.52 and

The experiment consists of choosing 5 players from the 6 that are declared. The other 7 players are not declaring for the NFL draft. The number of elements in the sample space, S, is C(13, 5). Because there are 6 players declaring, the number of ways of picking all 5 seniors is C(6,5). So, the probability of the event, E, of choosing all 5 seniors is:

28. The Polo Development Firm is building a shopping center. It has informed renters that their rental spaces will be ready for occupancy in 19 months.  If the expected time until the shopping center is completed is estimated to be 14 months, with a standard deviation of 4 months, what is the probability that the renters will not be able to occupy in 19 months?

-If both the items of interest and the items that are not of interest are least 5, the normal distribution can be used to approximate the binomial distribution.

b. What is the probability of failing on the first 2 trials and passing on the

Table below shows the distribution of the households covered by the RSS by their respective districts, Upazilla, Union and villages. RSS enlisted in total 3035 households in all 6 districts – of which 2132 were migrant families, and 903 non-migrants. The goal was to cover at least 300 migrant and 150 non-migrants households from each of the selected districts.