Enzyme Catalase Lab Report

The research and observations of this lab primarily focused on the enzyme activity of the enzyme Peroxidase. Peroxidase is a large protein and is composed of more than three hundred amino acids. The enzyme was selected as it is easy to experiment with and effectively showcases the effects of varying independent variables, such as pH and temperature. Peroxidase catalyzes the decomposition reaction of the chemical Hydrogen Peroxide ( H2 O2 ) into water and an electron donating molecule, which stands for R in the written chemical equation. ( The equation is displayed below:

Peroxidase is an enzyme found in potatoes that catalyzes the breakdown of hydrogen peroxide, H2O2, into O2 gas and water. We examined the different pH environments that can affect the enzyme activity during the breakdown of H2O2. In order to do this, we added different levels of pH, low, medium, and high, into different test tubes with the enzyme and H2O2, and we then inverted the tube. The amount of O2 gas produced was then measured and recorded. The result was that the higher pH produced more gas, followed by medium pH, then low pH. The enzymes were more active in the pH of about 10. It increased

The purpose of this experiment is to learn the effects of a certain enzyme (Peroxidase) concentration, to figure out the temperature and pH effects on Peroxidase activity and the effect of an inhibitor. The procedure includes using pH5, H202, Enzyme Extract, and Guaiacol and calibrating a spectrophotometer to determine the effect of enzyme concentration. As the experiment continues, the same reagents are used with the spectrophotometer to determine the temperature and pH effects on Peroxidase activity. Lastly, to determine the effect of an inhibitor on Peroxidase, an inhibitor is added to the extract. It was found that an increase in enzyme concentration also caused an increase in the reaction rate. The reaction rate of peroxidase increases at 40oC. Peroxidase performed the best under pH5 and declined as it became more basic. The inhibitor (Hydroxy-lamine) caused a decline in the reaction rate. The significance of this experiment is to find the optimal living conditions for Peroxidase. This enzyme is vital because it gets rid of hydrogen peroxide, which is toxic to living environments.

Students will label 3 test tubes hot, cold, and room temperature and place potato cub (3X3X3 cm)

The aim of this study was to test the rate of reactivity of the enzyme catalase on hydrogen peroxide while subject to different concentrations of an inhibitor. The hypothesis was that hydrogen peroxide will be broken down by catalase into hydrogen and oxygen, where a higher concentration of inhibitor will yield less oxygen, resultant of a lower rate of reaction. Crushed potato samples of equal weight were placed in hydrogen peroxide solutions of various temperatures. The results showed that less gas was produced as the concentration of the inhibitor rose. This Is because more enzymes were inhibited, and so less active sites were available for reaction.

Calculated volume of displaced oxygen (mL) when various amounts of hydrogen peroxide (mL) measured using a graduated cylinder were placed in the test tube with a liver solution soaked paper tab. Displaced volume of oxygen (mL) was calculated by subtracting the total volume by the resultant volume. The experiment was performed for one minute each time using a somewhat of an equivalent amount of liver solution for the remaining amounts of hydrogen peroxide (mL). The displaced volumes of oxygen (mL) were recorded in a data table along with the remaining trials. Detailed qualitative observations of various materials that were used during the experiment including hydrogen peroxide and liver solution were recorded.

Purpose To investigate how changes in the acidic pH level of an HCl solution will affect the rate at which the catalase enzyme will break down hydrogen peroxide into its products, oxygen and water. Hypothesis If the pH of the solution is related to the reaction rate of catalase, then changing the acidity of the environment will affect the decomposition rate of hydrogen peroxide because catalase has an optimal pH level at which it functions best. Since catalase is found throughout the human body (and highly concentrated in the liver), it is expected that the optimal pH of catalase will be similar to the pH of a human liver, which is maintained around 7 (neutral) (Science Buddies, 2012).

This experiment is designed to analyze how the enzyme catalase activity is affected by the pH levels. The experiment has also been designed to outline all of the directions and the ways by which the observation can be made clearly and accurately. Yeast, will be used as the enzyme and hydrogen peroxide will be used as a substrate. This experiment will be used to determine the effects of the concentration of the hydrogen peroxide versus the rate of reaction of the enzyme catalase.

The breakdown of hydrogen peroxide into water and gaseous oxygen is aided by peroxidase. This reaction can be distinguished by observing the oxygen bubbles produced.(Carter-Edwards et al. ,2011).The independent variable for this experiment was pH and temperature,dependant variable was height of bubbles in (cm) and size of balloon every 5 minutes for 20 minutes and the controlled variable were volume of hydrogen peroxide used

1mL of catalase (labeled liver extract) was injected into the Erlenmeyer flask with 10 mL’s of H2O2. The syringe was kept inside. Right after the 1 mL of catalase was injected into the 10mls of H2O2, the flask was swirled continuously. Then, it was observed if the reaction produced any O2 gas and was recorded in the data table. Each minute, the amount of O2 produced was

The purpose of this lab was to better understand the workings of the catalase enzyme when used in substrates (hydrogen peroxide), whilst experimenting with different factors that may affect the result of the reaction. All experiments and activities A, B, C, and D accept the hypothesis given for that activity. Hypothesis A stated if the catalase is added to the hydrogen peroxide, then the product of the chemical reaction will be water and oxygen. By following the experiment procedure, we can conclude that the resultant products of the reaction were water and oxygen by our observations. Hypothesis B stated that if we titrate a solution of H2O2, distilled water, and H2SO4, then we can determine the initial baseline amount of H2O2.

The enzyme that will be used in this experiment is catalase which can be found in animal or plant cells. The substrate that will be catalyzed by catalase is hydrogen peroxide (H2O2), toxic product in most living organisms. The catalase enzyme will catalyze the hydrolysis reaction of hydrogen peroxide into oxygen and water

Based on the prompt above, “You will design a lab to see if the enzyme Catalase (Peroxidase) can be denatured” we devised a hypothesis that states if you expose the Catalase to a pH that is not within its optimal working range, such as a pH of 2 and a pH of 12, the Catalase will denature because the catalase will only work in its optimal range that which is a pH of 7 (“PH Levels of Catalase.” 2017). The hypothesis that we have come up with proved to be incorrect 66% of the time as 2 out of the 3 trials above showed a reaction when we mixed the hydrogen peroxide with the Catalase. Although our results and observation states that 66% of the time Catalase and hydrogen peroxide has a reaction even when exposed to the different levels of pH, there

There were three test tubes in which the experiment was held. A relatively equal sized portion of raw potato (this contained the enzyme [a biological catalyst] hydrogen peroxidase) was placed in each tube. Then, enough water to cover the potato was added. Proceeding this, each of the test tubes were assigned a temperature; cold, room temperature or warm (this was written on the tag so that they were not confused). The test tube destinated ‘cold’ was placed in a ice bath for five minutes. At the same time, the ‘hot’ test tube was placed in a hot water bath for five minutes. Meanwhile, the room temperature test tube sat at room temperature for five minutes. When the five minutes were over, the test tubes were returned to the rack (so that they were able to be observed). Then, the test tubes were allowed to sit at room temperature for five more minutes. Once that period of time was over, 2 ml of hydrogen peroxide (the substrate) was added to each tube.

The test tube labeled number one was placed in ice water at 0° Celsius. The number two test tube was exposed to room temperature at 25° Celsius. The number three test tube was placed in boiling water at 100° Celsius. After three minutes, the bubble’s height of the three test tubes were measured