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Cmit Subnetting Assignment

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Subnet 90.0.0.0/8 into 260 subnets In order to get 260 subnets the subnet mask will need to have a range of 255.0.0.0 The IP Range will start at 1-254 since 0 and 255 will already be utilized. Netmask: 255.0.0.0 = 8 11111111 .00000000.00000000.00000000 Broadcast: 90.255.255.255 01011010 .11111111.11111111.11111111 Subnet 1 Network address: 90.0.0.0 Broadcast: 90.0.255.255 Available IPs: 90.0.0.1-90.0.255.254 Subnet 2 Network address: 90.1.0.0 Broadcast: 90.1.255.255 Available IPs: 90.1.0.1-90.1.255.254 Subnet 3 Network address: 90.2.0.0 Broadcast: 90.2.255.255 IP Range: 90.2.0.1-90.2.255.254 Subnet 4 Network address: 90.3.0.0 Broadcast: 90.3.255.255 IP Range: 90.3.0.1-90.3.255.254 Subnet …show more content…

For each of them, I need the following information: • The new subnet mask after the subnetting (10%) • The following information for the first FOUR subnets: o Subnet’s network address (3%) o Subnet’s broadcast address (3%) o Subnet’s range of available IP addresses (4%) • The calculations on how you get to the answers (50%). This is very important. If you don 't provide the calculations or the way you get the answer, you will lose 50%. 31 Subnet 70.0.0.0/8 into 230 subnets We need a minimum of 230 subnets so we do the calculation: 2^b >= 230 2^7=128 2^8=256 is the answer Subnet mask is now /8 +8 = /16 or 255.255.0.0 Subnet 1 Net ID: 70.0.0.0 Broadcast: 70.0.255.255 Available IPs: 70.0.0.1-70.0.255.254 Subnet 2 Net ID: 70.1.0.0 Broadcast: 70.1.255.255 Available IPs: 70.1.0.1-70.1.255.254 Subnet 3 Net ID: 70.2.0.0 Broadcast: 70.2.255.255 Available IPs: 70.2.0.1-70.2.255.254 Subnet 4 Net ID: 70.3.0.0 Broadcast: 70.3.255.255 Available IPs:

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