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Cation Flame Test Lab Report

Decent Essays

CH 204 – Introduction to Chemical Practice
Experiment 1 – (Qualitative Analysis of Cations)
Sania Razzak
Luis Andres Gonzales
TA: Jose Enriquez
February 11, 2016

RESULTS & DISCUSSION
The purpose of the experiment was to identify two cations in an unknown solution using qualitative analysis. The unknown solution contained metal nitrate salts. Part A was supposed to contain either silver or lead. Part B was supposed to contain either calcium or barium. In part C, cation flame tests were performed. This experiment taught basic solubility rules and how to write formula unit, total ionic, and net ionic equations. The experiment also helped to lean how to use the basic laboratory equipment.

If the experiment was repeated, step 1 should …show more content…

HCl was added because chloride is insoluble with lead and silver ions.1 Since HCl is soluble in water, applying heat at step 5 caused the bonds to break, which made it dissolve. In step 12 K2CrO4 was added to create a yellow precipitate. K2CrO4 was a good substance to use because it is insoluble with barium.1 The white precipitate of barium could be considered a false positive because the unknown substance could be calcium and the white precipitate would have made it seem as if it was barium.

The formula unit equation were K2CrO4 + Pb → PbCrO4 + K and K2C2O4 + Ca →CaC2O4 + K. The total ionic equation were K+ + CrO42- + Pb2+→ PbCrO4 + K+ and K+ + C2O42- + Ca2+→ CaC2O4 + K+. The net equations were CrO42- + Pb2+→ PbCrO4 and C2O42- + Ca2+→ CaC2O4.1

Centrifuge helped separate solids by liquids by making denser substance go to the bottom and less dense substance stayed at the top. To balance a centrifuge, equal volume had to be in all the test tubes and the weight had to be equally distributed. The Centrifuge must be balanced and when it was not balanced then the test tubes would burst.

The flame test can be used to identify a cation because each cation displayed a unique color. The problem was that multiple cations can display the same color and that some cations may overshadow another cations.

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