First, it was downloaded the spreadsheet from eLearn provided by the instructor titled as “Experiment I data”. The first thing, it was calculated the slope for each Time point and Response set of data. It was noticed that inhibitor concentration [I] was constant, and substrate [S] concentration was increasing. So, it was used the Response vs. Time data to allowed to measure the initial velocity [Vo] of the enzyme converting substrate to product. It was typed the formula “=slope(“ in the shift cell called “slope”. When it was typed the formula, it was selected the Y-values which is the Response column dragged down until the last response. Then, put a comma to separate the X-values which is the Time column followed by a closed parenthesis. Since, slope should be calculated for all of the others, it can be save time by doing …show more content…
To do this plot, it was took the reciprocal of everything. The reciprocal formulas used was “=1/”. It was selected the cell and typed the formula, and then selected the cell need it to do reciprocal of. It was started with B40, so it was like “=1/B40”. Since data was organized, it was used the black cross again to spread the formula around the other cells in the data set. It was repeated the same produce for I=5, 15, and 20 and for Inhibitor 2, and 3 to yield all to have the double reciprocal data. Finally, by doing these 3 graphs, can be calculated the Km and Vmax for each inhibitor concentration. To allow to do this, it was selected Chart, but now it was used Marked Scatter plots because this does not allow to connect the points. After, it was added the four inhibitor concentrations, added labels to the X and Y-axis, given a title, and selected Add Trendline. Then, it was selected “Display equation on the chart” and under Forescast was changed into 0.1 Periods in Backwards. This allowed to see where the X and Y-axis hit, and allow to determine the type of
3. State the name and structure of the functional group for each type of biologically
|(2 marks) | |c. |State two symptoms that may have led the veterinarian to suspect that George was suffering from a thyroid hormone |
Carbohydrates: any of a class of organic compounds that are polyhydroxy aldehydes or polyhydroxy ketones, or change to such substances on simple chemical transformations, as hydrolysis, oxidation, or reduction, and that form the supporting tissues of plants and are important food for animals and people.
Student instructions: Follow the step-by-step instructions for this exercise found on the worksheet below and in the virtual lab and record your answers in the spaces below. Submit this completed document by the assignment due date found in the Syllabus.
Surface Tension: The measure of how difficult it is to stretch or break the surface of a liquid.
In eukaryotes, stored primarily in the cell nucleus. A nucleic acid using deoxyribose rather than ribose.
* Palindromic: cut at the same base sequence on each strand, but in the opposite direction
Part A: 1) Extinct: A species that isn’t in existence anymore. 2) Extirpated: To get rid of a species completely. 3) Endangered: A species not extinct but is in danger of going extinct.
3a. Body more than five times as long as broad; front edge of dorsal fin far
K. Paraphrase the three potential fates of the excited electron produced when a photon meets a chlorophyll molecule
Varun Tandon AP Biology Homework 1. Ecology is the study of organisms and how they interact with the environment. The major subfields of ecology are organismal ecology, population ecology, community ecology, ecosystem ecology, landscape ecology, and biosphere ecology. Organismal ecology deals with how a specific organism interacts with and deals with challenges in an environment. Population biology deals with how the environment and other factors affect individuals of a population.
1. Information transfer is fundamental to all living organisms. For TWO of the following examples, explain in detail, how the transfer of information is accomplished.
Graph 6a (Substrate) – Represents a xy scatterplot with linear regression, which show the change in product concentration over the change in time at different substrate The data in the graph also gives the value of V0 at corresponding substrate concentration. Graph 6b (Substrate) – Represents a xy scatterplot depicting velocity of enzyme-catalyzed at multiple substrate concentrations. To find the concentration of the different absorbance in this experiment, a modified version of the Beer’s Law equation was used (C=A/k). The k which represents the slope in the equation was determine by using the date from Table 1 and points plotted in Graph 1. k=6.8339 the A in the equation is the measured absorbance which was determine by using a spectrophotometer.
Table I. Enzyme and velocity values for three different enzyme concentrations Run # Volume of enzyme stock (uL) [E] Enzyme concentration (ug/mL) b[1] Initial slope (∆abs/min) V Initial velocity (umol/min) 1 50 0.0030 ug/mL 0.1720 ∆abs/min 0.01433 umol/min 2 100 0.0060 ug/mL 0.3460 ∆abs/min 0.02884 umol/min 3 25 0.0015 ug/mL 0.0936 ∆abs/min 0.00700 umol/min v = (initial slope x volume in L) ÷ e x
Purpose: What is the purpose of this exercise? Are there any safety concerns associated with this exercise? If so, list what they are and what precautions should be taken. To understand the structure and function of multipolar neuron,unipolar and bipolar neurons. Also to identify the structures of a nerve. There are no safety concerns for this lab.