11 Standing Waves

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1610

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Physics

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Dec 6, 2023

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Justin Nandkishwar Physics Lab 1611 70122 December 1st, 2021 Lab Report Experiment 11: Standing Waves in a String Purpose The purpose of this experiment is for students to observe and understand the formation of standing waves and find the frequency of the string. Data n M + m hanger T v L λ f | f - <f>| 1 550g 539,000N 19,951.9cm/s 77.6cm 155.2cm 128.56Hz 0.13 2 140g 137,200N 10,066.3cm/s 77.6cm 77.6cm 129.72Hz 1.03 3 65g 63,700N 6,858.99cm/s 77.6cm 51.7cm 132.69Hz 4.0 4 35g 34,300N 5,033.13cm/s 77.6cm 38.8cm 129.73Hz 1.04 5 20g 19,600N 3,804.68cm/s 77.6cm 31.0cm 122.73Hz 5.96 Average < f > 128.69Hz (2) Calculate the % discrepancy between the average < f > of your data and the actual frequency fo = 120 Hz of the vibrating metal strip. 7.24% (3) Answer these questions: Q#1: What is the major reason for limiting your table to n=5, even if higher modes could be observed? The major reason for limiting the table to n=5 even if higher modes could be observed is because as you decrease the weight, the nodes will increase, and we wouldn’t have a lighter hanger to use. In addition, it would be hard to see the nodes to count when it passes 5 nodes. Q#2: Your string is similar to strings in a violin, in a piano, etc., which emit musical sounds. Did you hear some sound, and if you did, in which mode was it? If not, what should have been the main reason? (Hint: assume your hearing is perfect.) 51
I heard a faint sound at nodes 1 and 2 which is possible because the sound produced is within the hearing range of sound for humans. Anything beyond those nodes can’t be heard because the amplitude isn’t high enough to hear a sound. Q#3: Suppose n=1. If a 4% error is made in measuring M and a simultaneous 1% error is made in measuring L , then how big a % error in f this would cause, in the worst possible case ? What if it were ‘the other way around (1% for M and 4% for L )? (Note : you may want to try the method of differentials to answer this question. Otherwise some algebra will do.) When N=1 When N=1 λ =2L λ =2L Tension=mg Tension=mg V =√T / mu V =√T / mu V= λ f V= λ f V= 2Lf V= 2Lf 2Lf=√T / mu 2Lf=√T / mu 4f^2L^2=mg/u 4f^2L^2=mg/u Through differentiation Through differentiation 4f^2(2LdL)+4L^2(2fdf)= dmg/m 4f^2(2LdL)+4L^2(2fdf)= dmg/m 2dL/L+2df/f 2dL/L+2df/f 1% in L and 4% M 4% in L and 1% M ± 0.02+ ± 0.02x= ± 0.04 ± 0.08+ ± 0.08x= ± 0.01 0.02x=0.06 0.08x=0.09 x=3%--> 3% error in f x=1.125%--> 1.125% error in f 52
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