Lab 10 Ray Tracing

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LAB 10: Ray Tracing PHYSICS 1034 Jaymie Kocis Questions: 1. A shark with a laser flashlight (scary, isn’t it?) is pursuing a flying fish at night. Use Snell’s law (Eq. 10.5) to find the critical angle of incidence to the flashlight beam at the air-water boundary. Assume n = 1.00 for air and n = 1.33 for water. Snell’s Law: n 1 sin θ 1 = : n 2 sin θ 2 n 1 = 1.00 ;n 2 = 1.33 1.33 sinθ = 1 × 1 θ = 48.8 2. An object that is 1.0 cm tall is placed on the principal axis of a concave mirror whose focal length is 15.0 cm. The base of the object is 25.0 cm from the vertex of the mirror. Make a ray diagram with two or three rays that locate the image. Using the mirror equation (Eq. 10.8) and the magnification equation (Eq. 10.9), and the proper sign convention, calculate the image distance and the magnification. Is the image real or virtual? Is the image inverted or upright compared to the object? Is the image taller or shorter than the object? 1/u+1+v=1/f 1/v=1/f-1/u 1/v=1/15-1/25 V= 37.5 M= V/u=-37.5/25=-1.5 The image is real, inverted and taller.

3. An object that is 1.0 cm tall is placed on the principal axis of a convex mirror whose focal length is 15.0 cm. The base of the object is 25.0 cm from the vertex of the mirror. Make a ray diagram with two or the three rays that locate the image. Using the mirror equation (Eq. 10.8) and the magnification equation (Eq. 10.9), and the proper sign convention, calculate the image distance and the magnification. Is the image real or virtual? Is the image inverted or upright compared to the object? Is the image taller or shorter than the object? 1/u+1+v=1/f 1/v=1/f-1/u 1/v=1/15-1/25 V= 37.5 The image is real and inverted. M=-V/u=-37.5/25=-1.5 4. An object that is 1.0 cm tall is placed on the principal axis of a concave mirror whose focal length is 15.0 cm. The base of the object is 10.0 cm from the vertex of the mirror. Make a ray diagram with two or three rays that locate the image. Using the mirror equation (Eq. 10.8) and the magnification equation (Eq. 10.9), and the proper sign convention, calculate the image distance and the magnification. Is the image real or virtual? Is the image inverted or upright compared to the object? Is the image taller or shorter than the object? M=-1.5 The image is virtual, upright, and taller. 5. A thin lens is made of crown glass (n = 1.50). The radius of curvature for the first surface that an incident light ray encounters is 25.0 cm and this surface is bulging. The second surface of the lens that light encounters is hollow and has a radius of curvature of 20.0 cm. Using the lensmaker’s equation (Eq. 10.10), and the proper sign convention, calculate the focal length of this lens. Sketch a drawing of this lens, indicating its principal axis, principal focal point F, secondary focal point F′, and focal length f. F1= 25/2 F2= -20/2 1/f=(1.5-1)(1/25-1/20) 1/f= 0.5(20-25/(25(20)) 1/f=-1/200 f=-200

6. Why is the reflector behind the bulb in a flashlight ordinarily a parabolic mirror and not a spherical mirror? You may need to look up information about spherical aberration. Because a catenaric or hyperbolic arch, or any other style of mirror, will not efficiently scatter the light beams from the incandescent light bulb at the focal.

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