Lab 2 Blocking - for PLAR
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Mohawk College *
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Course
10004
Subject
Industrial Engineering
Date
Dec 6, 2023
Type
docx
Pages
7
Uploaded by CaptainTree12435
Lab 2: Design of Experiments 2k Factorial Design
The objective of this lab is to learn how to design and analyze 2
k-1
fractional factorial experiments using
Minitab.
The student will use their design results to determine optimal settings, significant factors, and
consider future design possibilities.
At the end of this lab, you should know how to:
1.
Discriminate between types of fractional designs.
2.
Select factors and responses; determine levels; select model terms; decide on design resolution and
control aliasing.
3.
Design and create an experimental worksheet for data collection.
4.
Predict future experimental results.
5.
Interpret output from the analysis of the experimental data
LAYOUT:
Create the needed graphs and data outputs in Minitab, then place the appropriate analysis and
questions with the Minitab content
.
Explain what you can learn about this data to a parent/boss/etc. Answer
each question with a full sentence and show only the Minitab output needed to answer each question. Marks
will be deducted for formatting, layout and style.
You may use this document as a template. Remove the question text but leave the numbers. Marks are noted
beside each question.
DUE: Your data (project file), and completed report (Activity 2.1 & 2.2)
This Final Report is 100% your original
individual work
. Use another student’s work, or content from the
internet or other sources, in your report will receive a 0
Activity 2.1: Four factor full design
Mark
s
A materials engineer at a plastic manufacturing company wants to increase the tensile strength of a plastic
product. The engineer identifies several factors to evaluate as possible contributors to tensile strength,
including processing temperature, additive, agitation rate, and processing time. A 2-level full factorial
design unreplicated (which means the design has one replicate in Minitab) is the initial experiment.
You
will also be exploring blocking and centre points.
To make analysis easier, you will be analysing with coded
levels (+1, -1) only.
1)
Full-factorial, no block
.
a)
Create the design worksheet in Minitab (4 factors
with 1
replicate)
.
Carefully fill out the command windows. You will
have a design worksheet with 16 runs.
b)
Enter the response data into the worksheet in standard
order from the table.
c)
Analyze this factorial experiment and include
all
terms in the
model. For Graphs, just create the
Pareto chart
of effects.
d)
Analyze again and include only terms up to order
2
. For
Graphs, just create the
Pareto chart
of effects.
Include your MiniTab here
:
For initial Analysis
o
Coded Coefficients Table
o
Model Summary
o
Pareto Chart
For Reduced Design
o
Coded Coefficients Table
o
Model Summary
o
Pareto Chart
/7
2)
Compare the Pareto Charts of effects.
Explain why, based evidence in these charts, we can drop all
terms above two-factor interactions.
What benefit in experimentation does this provide?
/3
3)
Full-factorial, block
on
replicate
The engineer would like to use two processing ovens.
To do so, she has
obtained the budget to run all factorial combinations twice resulting in a
total of 32 runs.
The oven is not a factor in the experiment but it may
cause possible nuisance variation that can be reduced by blocking.
Each
replicate of the design will be run as one block
a)
Again, create the factorial design worksheet in Minitab this time using
4 factors
and
2 replicates
.
Carefully fill out the command windows including:
/4
Temp
Additive
Rate
Time
Tensile
Strength
-1
-1
-1
-1
59.5
1
-1
-1
-1
58.5
-1
1
-1
-1
57.4
1
1
-1
-1
51.9
-1
-1
1
-1
56.5
1
-1
1
-1
61.3
-1
1
1
-1
58.1
1
1
1
-1
66.2
-1
-1
-1
1
53.2
1
-1
-1
1
59.5
-1
1
-1
1
57.5
1
1
-1
1
66.8
-1
-1
1
1
56.4
1
-1
1
1
68.5
-1
1
1
1
63.9
1
1
1
1
70.8
Designs
:
Number of replicates for corner points: 2.
Number of blocks: choose 2.
b)
Enter the response data into the worksheet in
standard order from the table below (your
worksheet will be stacked).
“Blocks” on your
worksheet will be the replicates:
c)
Analyze this factorial experiment and include only
terms up to order 2. For Graphs, just create the
Half Normal Plot of effects.
Include your MiniTab here
:
Coded Coefficients Table
Model Summary
Half Normal Plot
4)
Discuss
Oven
as a blocking variable.
Was it necessary to block? Why or why not? Provide evidence
from the output.
/3
5)
Full-factorial, block
on
highest order interaction (ABCD)
The engineer needs to use two processing ovens to complete the experiment in a timely fashion.
There is
no budget to run more than the 16 runs planned.
The oven is not a factor in the experiment but it may
cause possible nuisance variation that can be reduced by blocking.
In this case, we must use a different
technique for blocking which will result in the confounding of an interaction with the block (ovens).
a)
Again, create the factorial design worksheet in Minitab:
i.
Choose
Stat > DOE > Factorial > Create Factorial Design
.
ii.
Under Type of Design, choose
2-level factorial (specify generators).
In Number of
factors, choose
4
.
iii.
Click Designs. Choose Full Factorial, 0 center points and 1 replicate. In this window
click
Generators
and enter
ABCD
in the second box “Define blocks by listing their
generators (e.g.ABCD)”.
iv.
Click OK in all windows.
You will have a design worksheet with
16
runs with two Blocks (for ovens).
/4
Temp
Additive
Rate
Time
Tensile
Strength
Rep 1
Tensile
Strength
Rep 2
-1
-1
-1
-1
59.5
66.6
1
-1
-1
-1
58.5
59.5
-1
1
-1
-1
57.4
65
1
1
-1
-1
51.9
65.6
-1
-1
1
-1
56.5
56.1
1
-1
1
-1
61.3
58.6
-1
1
1
-1
58.1
62.6
1
1
1
-1
66.2
64
-1
-1
-1
1
53.2
63.9
1
-1
-1
1
59.5
64.2
-1
1
-1
1
57.5
63.3
1
1
-1
1
66.8
61.5
-1
-1
1
1
56.4
62.7
1
-1
1
1
68.5
68
-1
1
1
1
63.9
63.2
1
1
1
1
70.8
73.3
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b)
Enter the response data into the worksheet in
standard order from the table below.
“Blocks” on
your worksheet will be the
Oven
:
Analyze this factorial experiment and include only terms up
to order
2
. For Graphs, just create
the Half Normal Plot
of
effects.
Include your MiniTab here
:
Coded Coefficients Table
Model Summary
Half Normal Plot
6)
Discuss
Oven
as a blocking variable.
Was it necessary to block based on this output? Why or why
not? Provide evidence from the output. Discuss the method for blocking…issues?
7)
Centre points in a full-factorial.
The engineer would like to use centre points to explore potential non-
linearity in the factors.
a)
Create a
new design
worksheet
in Minitab
with
4 factors
,
1 replicate, 1 block and 3
centre points.
You will have a design worksheet with 19
runs with three
centre points.
b)
Enter the response data into the worksheet
in standard order from the table:
c)
Analyze this factorial experiment and include only
terms up to order
2
. For Graphs, just create the
Pareto Plot
of effects.
Include your MiniTab here
:
Coded Coefficients Table
Model Summary
Pareto Chart
8)
What evidence do we have/do not have for curvature? What benefit did adding centre points to
Oven
Temp
Additive
Rate
Time
Tensile
Strength
1
1
-1
-1
-1
58.5
1
-1
1
-1
-1
57.4
1
-1
-1
1
-1
56.5
1
1
1
1
-1
66.2
1
-1
-1
-1
1
53.2
1
1
1
-1
1
66.8
1
1
-1
1
1
68.5
1
-1
1
1
1
63.9
2
-1
-1
-1
-1
59.5
2
1
1
-1
-1
51.9
2
1
-1
1
-1
61.3
2
-1
1
1
-1
58.1
2
1
-1
-1
1
59.5
2
-1
1
-1
1
57.5
2
-1
-1
1
1
56.4
2
1
1
1
1
70.8
Temp
Additive
Rate
Time
Tensile
Strength
-1
-1
-1
-1
59.5
1
-1
-1
-1
58.5
-1
1
-1
-1
57.4
1
1
-1
-1
51.9
-1
-1
1
-1
56.5
1
-1
1
-1
61.3
-1
1
1
-1
58.1
1
1
1
-1
66.2
-1
-1
-1
1
53.2
1
-1
-1
1
59.5
-1
1
-1
1
57.5
1
1
-1
1
66.8
-1
-1
1
1
56.4
1
-1
1
1
68.5
-1
1
1
1
63.9
1
1
1
1
70.8
0
0
0
0
62.3
0
0
0
0
65.4
0
0
0
0
60.2
this experiment provide?
Activity 2.2: Four factor fractional design
The effect of four factors are being considered on cracks in components used for jet turbine engines.
The
four factors are (A) pouring temp, (B) titanium content, (C) heat method (categorical), and (D) amount of
grain refiner.
The length of cracks produced is the response being measured.
Goal: minimize length
9)
Full Factorial:
In Minitab, design a 2
4
full factorial (16 combinations) for this experiment with 1 replicate (16 runs).
Use the data given to analyse the experiment and determine the best model
Initially (I.), use all terms in the model (up through order 4).
Reduce (II.) the model as needed, by removing higher order terms (*remember the model
hierarchy!)
Remember to sort by StdOrder before copying the data to MiniTab
Include your MiniTab here
:
I.
For initial analysis
:
a.
Table of coded coefficients
b.
Model Summary
c.
Half normal
plot of the effects
II.
For reduced model:
d.
Table of coded coefficients
e.
Model Summary
f.
Half normal
plot of the effects
/6
10)
Compare the results between the full factorial and the ½ fractional factorial.
Which factors are
significant?
What differences do you see in the coefficients?
Do you come to the same
conclusion(s) with both designs?
/3
11)
What would be the benefit of the fractional design?
What would be the “risk” of running the
fractional design?
/2
12) Fractional Factorial:
Now consider that only a
one-half fraction of this 2
4
design
(2
4-1
)
could be run (8 combinations).
a)
Create the
2
4-1
in Minitab using the generator D=ABC (this is the default…no need to do anything).
Reference Step (1) of the Activity above to complete the design.
The design is un-replicated
(replicates = 1) and there is no blocking (blocks = 1).
StdOrder
Effect
Pour
temp(°C)
Titanium
content(%)
Heat
method
Grain
refiner(%)
Length
of crack
1
(1)
1000
3
Convection
5
7.0
2
a
1500
3
Convection
5
15.0
3
b
1000
4
Convection
5
11.0
4
ab
1500
4
Convection
5
17.0
5
c
1000
3
Fin
5
10.0
6
ac
1500
3
Fin
5
4.0
7
bc
1000
4
Fin
5
9.0
8
abc
1500
4
Fin
5
13.0
9
d
1000
3
Convection
10
8.5
10
ad
1500
3
Convection
10
17.0
11
bd
1000
4
Convection
10
14.0
12
abd
1500
4
Convection
10
19.0
13
cd
1000
3
Fin
10
12.0
14
acd
1500
3
Fin
10
6.0
15
bcd
1000
4
Fin
10
11.0
16
abcd
1500
4
Fin
10
16.0
Include your MiniTab here
:
Design Summary
Alias Structure
b)
Sort your worksheet by standard order and enter the
8 responses that match the runs in your
fractional design
matrix from the full table given above for the full factorial.
Name the column
“length of crack”
c)
Analyze the experiment with terms up to order 2.
Include your MiniTab here
:
Table of coded coefficients
Model Summary
/3
/3
13)
What would be the result if we also ran the alternate fraction?
/1
14)
Compare the effects between the full and fractional designs. How do they compare? Do you think
the extra work required to collect data for the full factorial was needed?
/3
15)
What resolution is the ½ fractional factorial and how do you know? (HINT: what is the alias
structure?)
What is the defining relation?
/2
16)
How did your prediction for the full factorial differ from the fractional factorial?
/1
17) Predictions
Now compare predictions from the full factorial to the fractional factorial.
Use the settings
1200
°C Pour Temp,
3.5
% Titanium Content,
Fin
Heat Method and
8
% Grain refiner:
a)
Predict the expected length of the crack for the full factorial model completed in 1).
Include your MiniTab here
:
Prediction results
b)
Predict the expected length of the crack for the fractional factorial model completed in 2).
Include your MiniTab here
:
Prediction results
/1
/1
2) If we have 15 factors, what is the least
number of runs we need to get a resolution IV design?
Why do we want a resolution IV design?
/3
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3) Play around with the other design options;
specifically:
a)
What does it mean “specify generators”?
How
would you use this option and for what?
b)
For what would you use the “General full
factorial design”? Give examples.
/2
/5