Lab_#3
pdf
School
Indiana University, Bloomington *
*We aren’t endorsed by this school
Course
109
Subject
Industrial Engineering
Date
Dec 6, 2023
Type
Pages
5
Uploaded by PresidentQuail3893
Part
1 Objectives
: ▪
To understand the procedures involved in the collection of simple meteorological data ▪
To construct a station model Answer the following questions: 1.
How would you code 1017.3 mb: __
173
______ 996.2 mb: _____
962
______ (10 points) 2.
What does 998 mean on a station model for pressure? (In other words, “unencode” this number, and include units.) ___
999.8
______
____________ (5 points)
Exercise 4
—
Introduction to meteorological instrumentation 1.
Using the internet (go to this link
) and enter city and state [Indianapolis, IN] and complete the first column. Next, enter the zip code [47405] or city and state [Bloomington, IN]), complete the second columns (again
make sure you record your units
). You might have to explore the NWS forecast page for Indianapolis and Bloomington to find all of the relevant data (20 points)
Indianapolis Airport (use weather.gov or noaa.gov) Bloomington/Monroe County Airport (use weather.gov or noaa.gov) Date/Time 9/21/2023 3:16 Pressure 1021.6 Pressure tendency Falling Cloud amount Mostly Cloudy Wind direction Se Wind speed 9 Precipitation No precipitation Temperature 80 Maximum temp. in last 24 hrs 78 Minimum temp. in last 24 hrs 64 Lab 4: Recording and Interpreting Meteorological Data: Station Models and Isopleths
Dew point temperature 57 Present weather Mostly Cloudy 2.
Carefully look at all the data you have gathered. Do the data values look reasonable? Discuss any differences you observe between the two cities and suggest possible reasons why they occur
. Consider both physical reasons (where was the data collected, how far apart were the locations, and so on
)
. What is the time difference between observations? How far apart (time wise) were the observations taken? What will be the effect of these differences? (5 points) For Questions 4 and 5, go to the following link to plot your station models using your observations.
link Be sure to save/insert or copy/paste your station models below. (10 points)
3.
Paste your Indianapolis data from the website in the standard format of the station model below here. 4.
Paste the station model from data from the website for the City of Bloomington, here.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Exercise 4
—
Part 2: Isoline maps and cross-sections 1.
Go to the link below and use the surface map with temperature data to draw isotherms at equal 10 o
F intervals to illustrate the pattern. On isoline maps there can be more than one maxima or minima. (
Remember to stop drawing isolines when you run out of data.) link
After you draw your map, see how your answers compare to the key (select “Draw Contour” for each isotherm in the “Review Answer” option). Be sure to either download or take a screenshot of your map and insert it below. (10 points) 2.
(a) Using the temperature in Chicago, IL and Bloomington, IN given in the map above and the distance between the two cities (~196 mi as the crow flies), calculate the temperature gradient (change in temperature per unit distance) between Chicago and Bloomington in °C/km
. Let’s say the temperature in Bloomington is 75 °F. Use the map to determine the temperature in Chicago and Bloomington. Be sure to show your work. (Note you will have to convert the temperature and distance data to °C and km) (20 points).
43 degrees F –
Chicago (43-32)X5/9 = 6.1 C Bloomington- 75F ( 75-32)X5/9= 23.89 C
Bloomington –
Chicago- = 17.7 C 196 miles 1 mile= 1.6 Km 196miles= 313.6 km 17.7/313.6= 0.056 C/km (b) Do the same for Bloomington, IN to Indianapolis, IN using the same temperature for Bloomington (75 °F) and a distance of 46 mi. Remember, you will need to convert the temperature and distance data to get the appropriate units (°C/km). Be sure to show your work (15 points).
Bloomington –
75(75-32)x5/9= 23.89C Indianapolis –
65(65-32)x5/9=18.3C Bloomington- Indianapolis= 5.59 46 miles 1 mile= 1.6km 46 miles= 73.9 km 5.59/73.9= 0.076 C/km 3.
Identify the area(s) on the map with the steepest temperature gradient
—
the region(s) where temperature changes most quickly over a short distance. Explain how you arrived at your answer (5 points).
60 degrees has the steepest temperature gradient because it is really close to the 50-70 degrees points so those area temperatures in the 60 degrees could have the quickest change in temperature in such a short time and distance because it is so close to both the 50- and 70- degree temperatures areas.