3-Kepler's Law KDA

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Feb 20, 2024

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Kevin Adriaens GSC1580 January 15, 2024 Kepler’s Third Law This assignment is best to do, turn in, and get feedback on before taking quiz #3. Do the following problems keeping in mind Kepler’s Third Law: the orbital period squared is equal to the average distance cubed, P 2 = a 3 The orbital period squared [P 2] is equal to the average distance cubed. P 2 = a 3 1. The orbital period squared of a Solar System object is P 2 = 56.0 years 2 , what is the average distance cubed, a 3 ? P 2 = 56 years 2 a 3 = 56 AU 3 2. The orbital period squared of a Solar System object is P 2 = 70.0 years 2 , what is the average distance cubed, a 3 ? P 2 = 70 years 2 a 3 = 70 AU 3 3. The average distance cubed of a Solar System object is a 3 = 84 AU 3 , what is the average orbital period squared, P 2 ? a 3 = 84 AU 3 P 2 = 84 years 2 4. The average distance cubed of a Solar System object is a 3 = 14 AU 3 , what is the average orbital period squared, P 2? a 3 = 14 AU 3 P 2 = 14 years 2 5. The orbital period of a Solar System object is P = 9.0 years, what is the average distance cubed, a 3 ? P = 9.0 year, 9 x 9, thus P 2 = 81.0 years 2 a 3 = 81 AU 3 6. The average distance of a Solar System object is a = 5.0 AU, what is the average orbital period squared, P 2? a = 5.0 AU, thus a 3 = 5 x 5 x 5 = 125 years 2 a 3 = 125 AU 3 P 2 = 125 years 2 7. The orbital period of a Solar System object is P = 7.0 years, what is the average distance cubed, a 3 ? P = 7 year, 7 x 7, thus P 2 = 49 years 2 a 3 = 49 AU 3 8. The orbital period squared of a Solar System object is P2 = 8.0 years 2 , what is the average distance, a? P 2 = 8 years 2 a 3 = 8 AU 3 a = 2
9. The average distance of a Solar System object is a = 4 AU, what is the average orbital period squared, P 2 ? a = 4 AU, thus a 3 = 4 x 4 x 4 = 64 years 2 a3 = 64 AU 3 P 2 = 64 years 2 10.The average distance cubed of a Solar System object is a 3 = 49 AU 3 , what is the average orbital period, P? a 3 = 49 AU 3 P 2 = 49 years 2 P = 7 years
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