RC Circuits worksheet

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School

Arizona State University *

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Course

132

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Electrical Engineering

Date

Dec 6, 2023

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pdf

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Uploaded by DeanMorning12527

1 O S C I L L O S C O P E S & R C C I R C U I T S – W O R K S H E E T Name: Andrew Crist Partners: Nahom, Hunter, Zainab TA: Rekha Joshi Part 1 – Oscilloscope basics: What happens when you switch the cables? Describe (or draw) the shape of the signal. When the cables are originally plugged in, the graph displayed represents a sin curve. When the terminals are switched, the signal seems not to follow any sort of pattern. The shape is very dense in relation to the previous sine wave, and the voltage seems to rapidly increase and then rapidly decrease. When is the signal displayed as a moving wave-train? When is it displayed as a still image? The signal is displayed as a moving wave train when the terminals are swapped, and when the terminals match then it is displayed as a still image. When the signal crosses over the y-axis, is the slope positive or negative in rising mode? In rising mode, when the signal crosses over the y-axis the slope is initially positive. What happens when you change the slope from rising to falling? When you change the slope from rising to falling, the graph is shifted along the x-axis so that the slope immediately after the y-axis is negative instead of positive. Clean-up/sign-out (3): Observations (20): Data/Analysis (20/30): Post Lab Q’s (15): Lab Report Total (88):

2 Measurements: ● Peak-to-peak voltage: 9.12 (unit: v) ● Voltage amplitude: 4.56 (unit: v) ● RMS voltage calculated: 3.22 (unit: v) ● RMS voltage measured (DMM): 3.163 (unit: v) ● RMS % difference: 1.79% Calculations Voltage Amplitude = 9.12/2 = 4.56v Period = 500microseconds * 2 = 1000microseconds RMS = V/(2)^1/2 = 4.56/(2)^1/2 = 3.22v RMS % difference = (3.163-3.22)/((3.163+3.22)/2) *100 = 1.79% Frequency = 1/t = 1/(1000*10^-6) = 1000Hz Part 2 – RC Time Constant ● R: 46.6 (unit: ohms) ● C: 994 (unit: nF) ● RMS 1000 Hz : 2.29 (unit: v) ● RMS 2000 Hz : 2.02 (unit: v) ● ! !"! "√" = ! # √" : (5/2)/(sqrt2) = 1.77 (unit: v) ∆࠵? 1/2 : 500 (unit: microseconds) Period: 1000 (unit: microseconds) Frequency: 1000 (unit: Hz) % difference from 1000 Hz: 0% τ DMM : 4.63*10^-5 (unit: seconds) τ measured : 46*10^-6 (unit: seconds) % difference: (Tmeasured-Tdmm)/avg= .65% ΔV = 5*.632 = 3.16 (unit: v)

3 POST-LAB QUESTIONS 1. From Part 2, draw the voltage waveform that was driving the circuit. Then, draw the waveform of the voltage across the capacitor. 2. At 2000 Hz, did the RMS voltage across the capacitor agree with the value of ! # √" ? Should these values have agreed? Why or why not? (Hint: read the first page of the introduction) The RMS voltage value did not agree with V0/(sqrt2). This is expected, as V0/(sqrt2) applies to sine wave voltage waveforms but we were not creating a sine wave voltage. 3. Why was the RMS voltage across the capacitor larger at 1000 Hz than at 2000 Hz? (Hint: think about how much time the capacitor spends near its maximum charge.) RMS voltage and peak to peak voltage have an inverse relationship with frequency. This is because higher frequencies charge and discharge the capacitor more frequently, meaning there is less charge build up (creating less of a difference) and therefore lower voltage.

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