Lab Exercise - Electrical Circuits and Battery Capacity-1

Find the equivalent resistance Rab for this circuit

Resistors Circuits I Each of the circuits below consists of a battery and several resistors. Several of the voltages, currents, and resistances are indicated. Use both of Kirchoff's Laws and Ohm's Law to determine as many of the other voltages, currents, and resistances as possible.

Find the Voltages and Currents for all the devices on the circuit below.

Redraw the circuit diagram of the simplified figure and find the current I flowing at resistance 8 ohm.

Q4) Determine the current through each resistor in the circuit of Figure R₁ 680 www R₂ 330 w R₁ 22092 w 10 mA

Write solution neatly. Thankyou!

Resistors Circuits I Each of the circuits below consists of a battery and several resistors. Several of the voltages, currents, and resistances are indicated. Use both of Kirchoff's Laws and Ohm's Law to determine as many of the other voltages, currents, and resistances as possible.

Resistors Circuits I Each of the circuits below consists of a battery and several resistors. Several of the voltages, currents, and resistances are indicated. Use both of Kirchoff's Laws and Ohm's Law to determine as many of the other voltages, currents, and resistances as possible.

a) Calculate the equivalent resistancein the following Figure.b) Find the potential difference andcurrent across each resistor.

C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot…

You connect a clamp-on ammeter and a voltmeter to a series LR circuit powered by a 60-Hz circuit. The voltage reads 120 V and the current is 0.715 A. The resistor is 150 W. What is the true power?

R2 18 kN RL 2 kN Vs 10 V R1 1.5 kN R3 330 N

What’s the percentage error?