Assignment-1_MM (1)

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Canadore College *

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5017

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Electrical Engineering

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Feb 20, 2024

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docx

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4

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ASSIGNMENT-1 Group-C ANANTHA NAGA SAI POOJARI (A00174072) ANUSHA NALLAPU (A00159054) SAMHITHA AKULA (A00173289) VENKATA SUDHEER SUNDARAP (A00145576)
1. Construct a frequency distribution table with 72 observations using class intervals, especially exclusive series. Why is it necessary to summarize data? Class Interval Frequenc y 50-53 11 53-56 10 56-59 8 59-62 10 62-65 10 65-68 12 68-71 11 2. Using the data range – calculate the standard deviation and interpret the result. Class Interval Frequenc y Midpoint di=(mi - 60.5)/ 7 fi. di di^2 fidi^2 standar d deviatio n 50-53 11 51.5 -1.286 - 14.14 3 1.653 18.184 6.1593 53-56 10 54.5 -0.857 -8.571 0.735 7.347 56-59 8 57.5 -0.429 -3.429 0.184 1.469 59-62 10 60.5 0.000 0.000 0.000 0.000 62-65 10 63.5 0.429 4.286 0.184 1.837 65-68 12 66.5 0.857 10.28 6 0.735 8.816 68-71 11 69.5 1.286 14.14 3 1.653 18.184 Sum 72 423.5 0 2.571 4 55.836 7 3. Calculate cumulative and relative frequency and discuss the relevance of both concepts in business. Class Interval Frequenc y cumulative frequency relative frequenc y 50-53 11 11 0.153 53-56 10 21 0.139 56-59 8 29 0.111 59-62 10 39 0.139 62-65 10 49 0.139 65-68 12 61 0.167 68-71 11 72 0.153
Sum 72 282 1 4. Calculate the average value for classified data and interpret the result. How are averages useful as a descriptive measure? Class Interval Frequenc y Midpoin t di=(mi- 60.5)/7 fi. di Averag e 50-53 11 51.5 -1.2857 - 14.1429 60.75 53-56 10 54.5 -0.8571 -8.5714 56-59 8 57.5 -0.4286 -3.4286 59-62 10 60.5 0.0000 0.0000 62-65 10 63.5 0.4286 4.2857 65-68 12 66.5 0.8571 10.2857 68-71 11 69.5 1.2857 14.1429 Sum 72 423.5 0.0000 2.5714 5. Distinguish between absolute and relative measures of variation. Compute and interpret the result of Mean absolute deviation and coefficient of MAD. Class Interval Frequenc y Midpoint (x) Average(x -) Modulous of (x- x-) f.(x-x-) MAD Co- MAD 50-53 11 51.5 60.75 9.25 101.75 5.354 1 8.8134 53-56 10 54.5 6.25 62.5 56-59 8 57.5 3.25 26 59-62 10 60.5 0.25 2.5 62-65 10 63.5 2.75 27.5 65-68 12 66.5 5.75 69 68-71 11 69.5 8.75 96.25 Sum 72 423.5 36.25 385.5 6. What purpose does a measure of variation serve? Using the data set, Calculate the standard deviation and advise the business firm on how they can meet the needs of their customers. Use variable as per need of statement. Class Interval Frequenc y Midpoint di=(mi - 60.5)/ 7 fi. di di^2 fidi^2 standar d deviatio n 50-53 11 51.5 -1.286 - 14.14 3 1.653 18.184 6.1593 53-56 10 54.5 -0.857 -8.571 0.735 7.347 56-59 8 57.5 -0.429 -3.429 0.184 1.469 59-62 10 60.5 0.000 0.000 0.000 0.000
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62-65 10 63.5 0.429 4.286 0.184 1.837 65-68 12 66.5 0.857 10.28 6 0.735 8.816 68-71 11 69.5 1.286 14.14 3 1.653 18.184 Sum 72 423.5 0 2.571 4 55.836 7