Week 8 BIOL133 Instructions
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American Public University *
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Course
133
Subject
Biology
Date
Jun 2, 2024
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The topic for week 8 is
Mendel's experiments and heredity.
In this
case study you will examine the evolution of cricket stridulation (cricket
calls) in the Hawaiian Islands, where a silent, non-stridulating phenotype
of
Teleogryllus oceanicus
has evolved and spread throughout Hawaiian
populations in just over a decade. This evolution and spread has been in
response to predation by a parasitoid fly that finds crickets to prey upon
via their calls.
You will learn how natural selection works and use simple Mendelian
crosses to uncover the genetic mechanism driving the change. You will
also be introduced to the most recent development in this evolutionary
case study, the appearance of a new phenotype that produces a purr-like
call. You will evaluate data that tests the hypothesis that this new call is
more attractive to female crickets than the silent phenotype while still
avoiding predation by the flies better than the ancestral call type.
Part A
Three C's (Content, Concern, Connection)
Content
: Pick something from this case study that stood out to you in
some way. It could be something new you learned, something that made
you think about this subject in a different way, or something you found
interesting. Share the content you chose with the class and explain why
you chose it.
Concern, or question
: After reviewing this case study, what is one
question or concern this content raised in your mind? This could be
something that didn't settle well with you, a question you have for future
research or consideration, or something you'd like to know more about.
Share this concern with the class and explain why you chose it.
Connection
: Why is the content in this case study important? How does
it relate to the real world and/or why is this case study important? You
could draw upon real world examples like something you read in the
news recently, something from your favorite TV show, or any other form
of connection between this case study and the importance of its content
outside the classroom.
Part B
Then, from the case study, answer the following questions
:
●
Part I: Answer questions 1, 2, and 3
●
Part II: Answer question 4a and 4b
●
Part III: Answer any 2 questions of choice
●
Review Parts IV and V
●
Part VI: Answer questions 11a, 11b, 12a, 12b
*Make sure you include the parts and question numbers in your post so
we know which questions you are answering (i.e. 'Part II, Question 4')
You must start your own post before you can see your
classmates' posts
Grading criteria:
Initial Post (40 points)
Reply Posts (30 points)
Creates Conversation and Community (15 points)
Terminology, Sources, and Attribution (15 points)
Initial Post Due: Wednesday by 11:59PM EST
Reply Posts Due: Sunday by 11:59PM EST
Your preview ends here
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Related Questions
Trivla Game Show
_Make Your Own Tri
ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566
Dillon WF
g
Aa v
Done
In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a
guinea pig that has black, rough hair? (Select all that apply.)
O BBRR
BBRr
BBrr
BBRR
BbRr
O bbRR
O bbRr
O bbrr
O Black
O White
O Rough
OSmooth
O Rough
O Smooth
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Let us practice it again! Analyze the pedigree below to answer the questions
that follow.
Huntington's disease a disorder in which nerve cells
waste away, or disintegrate, is passed down through families.
certain parts of the brain
Huntington's diseate
llustration ereated in htps://pregenygenetion.com/
1. What members of the family above are affected with the Huntington's
disease?
2. Tnere are no carriers ior Huntungton's disease you either have it or you do
not. Is Huntington's disease caused-by a dominant or recessive trait?
3. Identify the genotypes of the following individuals using the pedigree above.
(homozygous dominant, homozygous recessive, heterozygous).
I- 1
II -1:
II -3:
III - 4 :
4. How
many
children
did
individuals
I-1
and
I-2
have?
5. How many girls did II-1 and II-2 have? How many have Huntington's
Disease?
6. How are individuals III-2 and II-4 related?
I-2 and III-5?
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Pak Atan wants to know more!
Since Pak Atan know about the testcross, this time he tries
to determine the double trait of wool and eye of his beloved
sheep, Topokki. It is a male sheep with white wool and
brown eye. Help Pak Atan match Topokki with female
sheep to confirm its genotype. Show your work to Pak Atan.
(W = White wool ; w = Black wool)
(B = Brown eyes; b= Blue eye)
Shinta
Тоpokki
Dolla
Jajangmyeon
11-28
arrow_forward
Pak Atan wants to know more!
Since Pak Atan know about the testcross, this time he tries
to determine the double trait of wool and eye of his beloved
sheep, Topokki. It is a male sheep with white wool and
brown eye. Help Pak Atan match Topokki with female
sheep to confirm its genotype. Show your work to Pak Atan.
(W = White wool ; w = Black wool)
(B = Brown eyes; b= Blue eye)
%3D
Shinta
Тоpokki
Dolla
Jajangmyeon
11-28
Copyright ©2019 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior written consent of McGraw-Hill Education.
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My Courses
D
uizzes/4305259/take
Question 2
O 0%
x EBook - SRH - Go__ x
X
x Book Outline-SF X
In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these
alleles are dominant over albino (c). Heterozygotes may be single-coal colored (e.g., CWc) or
multi-coat colored (CWCB).
O 25%
If a heterozygous black-coated rabbit and a homozygous white-coated rabbit mate, what is
the likelihood that offspring rabbits will be spotted?
O 50%
O 75%
Question 3
Quiz: M6 TYK - MX
Q Search
1 pts
Com L
The next set of questions focus on the ABO blood typing system.
What inheritance pattern(s) does the ABO blood type demonstrate? Select all that are correct.
0.5 pts
Mail
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TOPIC : Genetics
Example's for Question
GENE = Hair Color
ALLELE = Straight, Curly
DOMINANCE = BB
RECESSIVE = bb
GENOTYPE = BB, Bb, bb
PHENOTYPE = Blue, Black
HOMOZYGOTE = BB (Blue eye), bb (Black eye)
HETEROZYGOTE = Bb (Blue eye)
MONOHYBRID = Aa
DIHYBRID = AaBb
TRIHYBRID = AaBbCc
POLIHYBRID = AaBbCcDd
MENDELLIAN GENETICS = Hair Color
NON MENDELLIA = Blood Type
QUESTIONS:
Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!)
1. MONOHYBRID CROSS = ?
DIHYBRID CROSS = ?
2. BACK CROSS = ?
TEST CROSS = ?
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PLEASE ANSWER 4 & 5
Below in Figure 1 is a pedigree for a family afflicted by a genetic disorder. In some populations, Cystic fibrosis has an incidence of 1 in 2500 newborns. The carrier frequency calculated from this is 1/25. Analyze the pedigree below assuming the disease is similar to cystic fibrosis in incidence and carrier frequency. However this disease may not have the same type of genetic transmission as cystic fibrosis.
What type of genetic transmission is most consistent with the pedigree?
Label all the individuals that you can determine, with hypothesized genotypes.
Label the individuals that have unknown genotypes with possible genotypes.
Assuming her father is known to NOT be a carrier, calculate the probability that IV1 is a carrier for disease.
Use the Χ2 test to determine whether your proposed transmission fits this data.
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The linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. In a large sample of the Venezuelan family, what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?
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E-
Question 20/28
In chart 1, the offspring of the two pea plants are Aa.
Use the diagrams below to answer the questions that follow.
This is known as .
Pea Plants
A Homozygous Dominant
Chart 1
Homozygous Recessive
Punnett Square
Heterozygous Dominant
Heterozygous Recessive
Aa
Aa
Aa
Aa
Chart 2
AaBb x AaBb
AB
Ab
qe
AaBb
ав
Key
AB AABB AABB
AABB
AA-Green
Ab AABB AAbb AaBb
Aabb
BB- Smooth
aa - Yellow
aB AABB
AaBb
aaBB
aaBb
ab AaBb
y6noy - 99
Aabb
aaBb
aabb
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PLEASE explain how to do this question step by tspe i am very confused! thank you!
You have three independent mutant alleles in the Drosophila gene no legs (nlg): nlg1, nlg2, and nlg3. You assay the phenotype of Drosophila, which is an insect, that are heterozygous for the three allele (heterozygous for a wild-type and a mutant allele), and that are homozygous for the three alleles.
Allele
nlg1
nlg2
nlg3
heterozygous
Wild-type
Four pairs of legs
Wild-type
homozygous
Stumpy legs
Five pairs of legs
No legs
nlg1 is a ___X___ allele, nlg2 is a ___Y___ allele, and nlg3 is a ___Z___ allele.
X
Y
Z
A
Gain of function
Null
Hypomorphic
B
Hypomorphic
Gain of function
Null
C
Null
Gain of function
Hypomorphic
D
Null
Hypomorphic
Gain of function
E
Hypomorphic
Null
Gain of function
Referencing the table above, select the correct answer:
1 : A
2 : B
3 : C
4 : D
5 : E
Correct answer is B
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W
O () ENG
9:37 am
O GENBIO-1ST-SEM-MIDTERN X
9 Schoology
G karyotype of a certain huma x
6 BigBlueButton - GNBIO
Messenger
My Questions | bartleby
+
A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401
The diagram below shows a karyotype of a certain human.
8.
10
11
12
13
14
15
16
17
18
19
21
22
X Y
Based on the karyotype, which of the following statements is most likely true?
O The individual has a genetic condition caused by a nondisjunction event.
The individual has a genetic condition caused by the X and Y chromosomes being different
sizes.
O The individual has a genetic condition caused by a chromosomal duplication.
O The individual has a genetic condition caused chromosomes number one being different sizes.
GENBIO-1ST-SEM-.pdf
O 245180335_56899...jpg
Show all
...
TID N
DAD ×
IDD .
I ID.
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Agree or disagree with each of the five statements below and describe why the statement is or is not true. Number your answers so I know which statement you're talking about.
Berdon syndrome is a recessive disorder in humans that is typically fatal shortly after birth. This disease will eventually be eliminated from the population because people with the disease die before they reproduce.
Jalili syndrome is an extremely rare recessive disorder. A person with one normal allele and one disease allele will not suffer from this disorder.
The ability to taste the chemical phenylthiocarbamide (PTC) is a dominant trait in humans. Therefore, the majority of the population must have this trait.
An individual's phenotype is determined entirely by their DNA.
All mutations are harmful.
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Stil confused on part 3.
3. Use the chi-squared test to determine if these data fit the Hardy-Weinberg equilibrium model.
The degrees of freedom for this test should be 1. Why is this appropriate?
Is the hypothesis accpeted because the chi square value calulated is less than the critical value from the chart? And why do we use df=1? Is it because we're only looking at 2 alleles?
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Questions:
1. Length of fur is also genetically determined. The allele L produces long fur and its corresponding allele,
I, produces short fur. Long fur is dominant to short.
a) You mate 2 hamsters. Both heterozygous for brown long fur. Would you expect any of the
offspring to have black short fur? If so, what proportion would have black short fur?
b) What proportion would have black long fur?
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/d/1n5NtidRwTwUzcDkDPi5Z9P_SHPZ91A-XH-pfftLbhNc/edit
(1) O
pols Add-ons Help
Last edit was seconds ago
BIUA
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Calibri
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Section 5: Trihybrid cross and Laws of probability
For a trihybrid cross, in which inheritance of alleles for three genes is tracked, drawing a
Punnett square that combines all three genes may not be practical. Instead the laws of
probability may be used. The product law of probabilities says that when alleles for separate
genes segregate independently, we can figure out the probability of a particular combined
genotype by multiplying the probability of the alleles for each gene.
13. We cross a homozygous tall pea plant with yellow, round seeds to a homozygous dwarf
pea plant with green, wrinkled seeds. All the F1 offspring are all tall plants with yellow,
round seeds.
a. What are the expected F2 ratios (use fractions) of tall and dwarf plants?
b. What are the expected F2 ratios (use fractions) of yellow and green seeds?
C. What are the expected F2…
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Choice 2: Black versus orange fur is determined by two alleles an X-linked gene (XⓇ, Xº), Suppose that a black male is mated
with an orange female.
a) Write the genotypes of the male and female cats.
Male:
Female:
b) What genotypes & phenotypes are expected among the offspring (F1) of these parent cats?
c) Suppose that a male and a female from part b mate. What offspring types will they produce?
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Directions: Match the word on the left to the correct picture on the right. Write the # in the circle.
Word
Picture
1. Dominant
2. Recessive
3. Trait
4. Punnett Square
Aa
aa
5. Pedigree
a
Aa
aa
6. Gregor Mendel
7. Genotype
8. Phenotype
AaBb
9. Genetics
Father's Genes
10. Heteozygous
G GG Gg
9 Gg g9
B BB
Bb
11. Homozygous
12. Hybrid
bBb
bb
13. Allele
14. Heredity
Crossing between a red rose and a
white rose producing a pink phenotype.
15. Incomplete
Dominance
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Question ?
Question 7
The ability to taste certain substances, such as PTC is
also genetically controlled. People that can taste
have a dominant allele (T), while non-tasters have
the recessive alleles (tt). Suppose a woman who is a
non-PTC-taster has offspring with a man who is a
homozygous PTC taster. What is the probability that
they have a child with the tasting gene?
A 25%
e 50%
© 75%
O 100%
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questions below: Aura and Ryan are expecting a child. Aura has dark eyes and
Ryan has light eyes. Aura's mother has light eyes.
Draw a Punnett square and be sure to include the following information for full
credit:
1. Place the parents alleles at the top and on the left side.
2. Write in the allele crosses inside the Punnett squares.
3. Write out the genotypes probabilities for an offspring.
4. Write out the phenotype probabilities for an offspring.
5. What is the probability that Aura and Ryan could have a child with light eyes,
even if light is recessive to dark?
Note: For this question, you will have to go further back into the family tree to
get Aura's genotype.
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Isaac Reynolds - Genetics and H X
G what is another word for genetic X +
m/d/1gmCOqwX_FMMXE_R4XOB7eq1pQgl-tXFHs6zVrbFYlmk/viewer
s and Heredity Vocabular... <
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please help me answer these questions. THANK YOU!
1. In relation to codominance and incomplete dominance. What do you think is the reason for the occurrence of these two patterns or modes of transmission of inheritance in plants and animals?
2. What are the similarities and the differences between codominance and incomplete dominance?
3. In 3 sentences. What are the reasons for the occurrence of codominance and incomplete dominance traits?
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Question t Incorrect
Question t
The ability to taste certain substances, such as PTC is
also genetically controlled. People that can taste
have a dominant allele (T), while non-tasters have
the recessive alleles (tt), Suppose a woman who is a
non-PTC-taster has offspring with a man who is a
homozygous PTC taster. What is the probability that
they have a child with the tasting gene?
A 25%
B 50%
©75%
O 100%
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Student Name: Alyssa york
The Hardy-Weinberg Equation
4. Cystic fibrosis is a homozygous recessive condition that affects 1 in 10,000 of the Hispanic population
in the United States. Calculate the frequency of the dominant allele, the frequency of the recessive
allele, and the percentage of heterozygous individuals (carriers) in the Hispanic population.
P
qFrequency of the
recessive allele
2
p²
q²
Frequency of the
dominant allele
2pq
% homozygous dominant
% homozygous recessive
% heterozygous
0.98
0.02
96.04.7.
0.0.4%
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Questions:
1. Length of fur is also genetically determined. The allele L produces long fur and its corresponding allele,
I, produces short fur. Long fur is dominant to short.
a) You mate 2 hamsters. Both heterozygous for brown long fur. Would you expect any of the
offspring to have black short fur? If so, what proportion would have black short fur?
b) What proportion would have black long fur?
2. In cats, yellow coat color is due to a gene, b, and black coat color is due to its allele, B. The alleles b
and B are sex-linked (i.e. are located on the X chromosome). Because of Barr body formation, the
heterozygous condition results in tortoise shell colored cats (both black and yellow patches).
a) What kinds of offspring would be expected from the mating of a black male with a yellow
female?
b) Of a yellow male with a tortoise female?
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Hi, I'm having some trouble with this practice problem from my study guide. If anyone can explain it it would be very helpful!
Brindle coloration is a black and brown striping pattern in some dogs. This fur coloration is controlled by different alleles at a single autosomal locus. There are three alleles, KB, kbr and ky. The KB allele is dominant over the other two alleles and produces a solid black color. The allele kbr produces the brindle color pattern and is dominant over the ky allele, which produces yellow fur. Give the genotypes of the parents and offspring in each cross.
P: black X yellow; F1: ½ brindle and ½ black
P: black X brindle; F1: ½ black, ¼ brindle and ¼ yellow
P: brindle X yellow; F1: 100% brindle
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2) The year is 2050. The climate has continued to warm. Areas in northern Canada and Alaska are without snow or ice; the average annual temperature has risen and previously snow-covered areas are now shrub land and some temperate forests. What effect would such a climatic change have on the gene pool of the rabbits? All BUT ONE could apply.
A) The allelic frequency has most likely shifted to 85% GG and 15% gg.
B) The dominant allele in the gene pool would become G, the previously rare allele.
C) The allele for white, g, would be scarce and perhaps nonexistent in the population.
D) White rabbits would be at a disadvantage in terms of camouflage and would likely fall prey to predators.
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acari Brigham: Attempt 1
Question 7 (1 point)
Farmer Betty is famous for her winged pigs. Having wings (G) is dominant over not
having wings (g). Farmer Betty mates a winged pig to one without wings (GG x gg)
and all of the offspring are heterozygous (Gg). Do the heterozygous piglets have
wings?
Yes
No
OHalf of them do
Question 8 (1 point
n peas.tong sem Als dominant oversho stem (a) Aheterozygous long stem
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Hello, I need help answering 3.a, b, & c questions. Pls and thank you
3. A.) Study of mutations reveals that:
a.) mutations that lead to shortened proteins often have high negative selection coefficients
b.) most mutations that affect fitnes are synonymous mutations
c.) most non-synonymous mutations have positive selection coefficients
d.) mutations that have major effects on the phenotype are the most common.
B.) Natural selection during the final stage of allopatric speciation can cause:
a.) increased post-zygotic isolation in a hybrid zone
b.) more gene flow to form a "hybrid swarm"
c.) increased pre-zygotic isolation in a hybrid zone
d.) negative assortive mating
C.) Human hunting of wild animals, such as deer or bighorn sheep, usually:
a.) leads to evolution in the same direction as that favored by natural selection in the non-hunted populations
b.) causes males to have more extreme sexual characters (such as horn size)
c.) creates artificial selection in a direction that…
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How do I explain this? Phenotype is what we can see externally and you can't see cystic fibrosis so the phenotypic ratio should be zero right? And the genotypic should be 1:2:1? Or am I wrong?
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21 words
Question 10
In some species of petunias (flowers), red flowers are dominant and white flowers are recessive. Heterozygotes are pink in
color. What is the genotype of the parents that would product 100% pink offspring?
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Related Questions
- Trivla Game Show _Make Your Own Tri ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566 Dillon WF g Aa v Done In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a guinea pig that has black, rough hair? (Select all that apply.) O BBRR BBRr BBrr BBRR BbRr O bbRR O bbRr O bbrr O Black O White O Rough OSmooth O Rough O Smootharrow_forwardLet us practice it again! Analyze the pedigree below to answer the questions that follow. Huntington's disease a disorder in which nerve cells waste away, or disintegrate, is passed down through families. certain parts of the brain Huntington's diseate llustration ereated in htps://pregenygenetion.com/ 1. What members of the family above are affected with the Huntington's disease? 2. Tnere are no carriers ior Huntungton's disease you either have it or you do not. Is Huntington's disease caused-by a dominant or recessive trait? 3. Identify the genotypes of the following individuals using the pedigree above. (homozygous dominant, homozygous recessive, heterozygous). I- 1 II -1: II -3: III - 4 : 4. How many children did individuals I-1 and I-2 have? 5. How many girls did II-1 and II-2 have? How many have Huntington's Disease? 6. How are individuals III-2 and II-4 related? I-2 and III-5?arrow_forwardPak Atan wants to know more! Since Pak Atan know about the testcross, this time he tries to determine the double trait of wool and eye of his beloved sheep, Topokki. It is a male sheep with white wool and brown eye. Help Pak Atan match Topokki with female sheep to confirm its genotype. Show your work to Pak Atan. (W = White wool ; w = Black wool) (B = Brown eyes; b= Blue eye) Shinta Тоpokki Dolla Jajangmyeon 11-28arrow_forward
- Pak Atan wants to know more! Since Pak Atan know about the testcross, this time he tries to determine the double trait of wool and eye of his beloved sheep, Topokki. It is a male sheep with white wool and brown eye. Help Pak Atan match Topokki with female sheep to confirm its genotype. Show your work to Pak Atan. (W = White wool ; w = Black wool) (B = Brown eyes; b= Blue eye) %3D Shinta Тоpokki Dolla Jajangmyeon 11-28 Copyright ©2019 McGraw-Hill Education. All rights reserved. No reproduction or distribution without the prior written consent of McGraw-Hill Education.arrow_forwardMy Courses D uizzes/4305259/take Question 2 O 0% x EBook - SRH - Go__ x X x Book Outline-SF X In rabbits, white coat color (CW) and black coat color (CB) are codominant, and both of these alleles are dominant over albino (c). Heterozygotes may be single-coal colored (e.g., CWc) or multi-coat colored (CWCB). O 25% If a heterozygous black-coated rabbit and a homozygous white-coated rabbit mate, what is the likelihood that offspring rabbits will be spotted? O 50% O 75% Question 3 Quiz: M6 TYK - MX Q Search 1 pts Com L The next set of questions focus on the ABO blood typing system. What inheritance pattern(s) does the ABO blood type demonstrate? Select all that are correct. 0.5 pts Mailarrow_forwardTOPIC : Genetics Example's for Question GENE = Hair Color ALLELE = Straight, Curly DOMINANCE = BB RECESSIVE = bb GENOTYPE = BB, Bb, bb PHENOTYPE = Blue, Black HOMOZYGOTE = BB (Blue eye), bb (Black eye) HETEROZYGOTE = Bb (Blue eye) MONOHYBRID = Aa DIHYBRID = AaBb TRIHYBRID = AaBbCc POLIHYBRID = AaBbCcDd MENDELLIAN GENETICS = Hair Color NON MENDELLIA = Blood Type QUESTIONS: Give Example of the following fo differentiate, DO NOT GIVE THE MEANING! (Follow the instructions above!) 1. MONOHYBRID CROSS = ? DIHYBRID CROSS = ? 2. BACK CROSS = ? TEST CROSS = ?arrow_forward
- PLEASE ANSWER 4 & 5 Below in Figure 1 is a pedigree for a family afflicted by a genetic disorder. In some populations, Cystic fibrosis has an incidence of 1 in 2500 newborns. The carrier frequency calculated from this is 1/25. Analyze the pedigree below assuming the disease is similar to cystic fibrosis in incidence and carrier frequency. However this disease may not have the same type of genetic transmission as cystic fibrosis. What type of genetic transmission is most consistent with the pedigree? Label all the individuals that you can determine, with hypothesized genotypes. Label the individuals that have unknown genotypes with possible genotypes. Assuming her father is known to NOT be a carrier, calculate the probability that IV1 is a carrier for disease. Use the Χ2 test to determine whether your proposed transmission fits this data.arrow_forwardThe linkage distance between the DNA sequence used in the test and the actual Huntington’ disease locus was 5%. In a large sample of the Venezuelan family, what percentage of people would inherit the DNA sequence but not the Huntington’s allele (i.e. be a false positive test for Huntington’s)? What percentage of that large Venezuelan family would not inherit the DNA sequence but would inherit the Huntington’s allele (i.e., be a false negative test for Huntington’s)?arrow_forwardE- Question 20/28 In chart 1, the offspring of the two pea plants are Aa. Use the diagrams below to answer the questions that follow. This is known as . Pea Plants A Homozygous Dominant Chart 1 Homozygous Recessive Punnett Square Heterozygous Dominant Heterozygous Recessive Aa Aa Aa Aa Chart 2 AaBb x AaBb AB Ab qe AaBb ав Key AB AABB AABB AABB AA-Green Ab AABB AAbb AaBb Aabb BB- Smooth aa - Yellow aB AABB AaBb aaBB aaBb ab AaBb y6noy - 99 Aabb aaBb aabbarrow_forward
- PLEASE explain how to do this question step by tspe i am very confused! thank you! You have three independent mutant alleles in the Drosophila gene no legs (nlg): nlg1, nlg2, and nlg3. You assay the phenotype of Drosophila, which is an insect, that are heterozygous for the three allele (heterozygous for a wild-type and a mutant allele), and that are homozygous for the three alleles. Allele nlg1 nlg2 nlg3 heterozygous Wild-type Four pairs of legs Wild-type homozygous Stumpy legs Five pairs of legs No legs nlg1 is a ___X___ allele, nlg2 is a ___Y___ allele, and nlg3 is a ___Z___ allele. X Y Z A Gain of function Null Hypomorphic B Hypomorphic Gain of function Null C Null Gain of function Hypomorphic D Null Hypomorphic Gain of function E Hypomorphic Null Gain of function Referencing the table above, select the correct answer: 1 : A 2 : B 3 : C 4 : D 5 : E Correct answer is Barrow_forwardW O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.arrow_forwardAgree or disagree with each of the five statements below and describe why the statement is or is not true. Number your answers so I know which statement you're talking about. Berdon syndrome is a recessive disorder in humans that is typically fatal shortly after birth. This disease will eventually be eliminated from the population because people with the disease die before they reproduce. Jalili syndrome is an extremely rare recessive disorder. A person with one normal allele and one disease allele will not suffer from this disorder. The ability to taste the chemical phenylthiocarbamide (PTC) is a dominant trait in humans. Therefore, the majority of the population must have this trait. An individual's phenotype is determined entirely by their DNA. All mutations are harmful.arrow_forward
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