Write the sequential procedure for making the simple step turning operation for making t shown job – 400
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- Write the sequential procedure and CNC code for making the simple step turning operation for making the shown job - 100 15-1 42 Size of Raw material Total Length = 100 mm, Free length out of Clamping device = 70 mm, Diameter = 42 mm, this has to be reduced to 10 mm, 20 mm, 30 mm, diameter for a length of 15 mm steps each as shown above diagram.Draw the p-V and T-s diagrams in each problems.Here's what I got for part 1 (first attachment) of the problem, I need help correcting the second part (second attachment) of the problem with step-by-step calculations.
- STATICS : METHOD OF SECTIONS - GET THE GIVEN, WHAT IS ASKED, AND THE ANSWER. - MAKE A PROPER FREE BODY DIAGRAM. (IT DOES HAVE THE GREATER POINTS IN THIS ACTIVITY) - YOUR SUB ANSWERS MUST BE IN 6 DECIMAL PLACES. - YOUR FINAL ANSWER MUST BE IN 4 DECIMAL PLACES. - TELL THE DIRECTION AND WHETHER IT IS TENSILE OR COMPRESSION. - WRITE YOUR SOLUTION PROPERLY (EASY TO UNDERSTAND). - I PROVIDED A SAMPLE PROBLEM SO THAT YOU WILL KNOW HOW TO SOLVE IT. THANK YOU IN ADVANCE! Solve the forces in PQ, FL, QG, and QM. Hint: Identify all zero-force members and remove them from the structure. In the summation of moments, look for a point where member forces at the supports converge so that their moment arm is zero. From here you will be able to solve PQ. Solve FL using summation of moments from the other half of the section. Solve QG and QM using Method of Joints.8Given the material composition is 2024 aluminum with two different material thickness. The skin is 0.040" material thickness and the patch is 0.032" of material thickness with crack length of 2". Calculate the rivet diameter, rivet length, rivet pitch, transverse pitch and edge distance for the repair layout.The forces shown in the following figure act on a specific screwed part. It can be noted that none of them acts directly on the known x and y axes. With this, what should be the force component acting on these axes? Options: a) The force on the x-axis is 20.54 N; and on the y-axis, it is 250.22 N. B) The force on the x-axis is -20.54 N; and on the y-axis, it is 230.22 N. c) The force on the x-axis is -22.54 N; and on the y-axis, it is 190.98 N. d) The force on the x-axis is 21.20 N; and on the y-axis, it is -234.89 N. e) The force on the x-axis is -20.54 N; and on the y-axis, it is 250.22 N.
- I need problem 8 answered pertaining to the print and sequence of operations that is both provided.Please answer the problem with FREE BODY DIAGRAM AND COMPLETE SOLUTIONS. Also, box the final answer and explain the step-by-step solutions. Thank you! GUARANTEED UPVOTE!!!! STRENGTH OF MATERIALS Topics: Torsion Flanged Bolt Couplings Torsion of Thin-Walled Tube Helical Springs PROBLEM:The turbine motor moving at 378 rev/ min can produce 2.5 hp. The shaft diameter is 1.25 inches. Calculate the torque and shearing stress developed in the shaft.What are the TPI and TPF of a part with end diameters of 3/4" and 1/2" and a taper length of 4.25"?
- Follow up: How would the steps of this problem change if θ was not 90°?Using method of joints Calculate with working out, every member (Only 1/2 the sides needs to be done) - The green arrows represent 5N each downwards - and each support is a roller with 7.5N acting upwardsPlease follow the problem direction and show a free body diagram if possible, thank you!