Write down a simple code for stroing studnet data in a link list. You must be able to search the record of a particular student and display it on demand. the following information must be stored. 1. student full id e.g sp17-bcs-009 2. student name 3. student current semester 4. student CGPA
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Data Structures and
Note: Write it using Structures
Q. Write down a simple code for stroing studnet data in a link list.
You must be able to search the record of a particular student and display it on demand.
the following information must be stored.
1. student full id e.g sp17-bcs-009
2. student name
3. student current semester
4. student CGPA
Step by step
Solved in 2 steps with 1 images
- Using C Programming: Each student in the university may take a different number of courses, so the registrar has decided to use a linked list to store each student’s class schedule and to use an array of structures to represent the whole student body. A portion of this data structure follows.The records show that the first student (array element 0, id 1111) is taking Section 1 of CIS120 for 3 credits and Section 2 of HIS001 for 4 credits; the second student (array element 1, id 1234) is not enrolled, and so on. Define the necessary data types for creating this structure. Provide operators for creating the original array of student ID numbers, inserting a student’s initial class schedule, adding a course, and dropping a course. Write a menudriven main function to use this structure. Menu-driven main function can be something like this: After each operation that the user selects, it will show a menu and will wait for the user’s input. Such as: 1-Add course, 2-Drop course, 3-Insert…The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. List all copies of the book title “Lord of the Rings” that are available for borrowing. List the names of borrowers who currently have the book title “Lord of the Rings” on loan. List the names of borrowers with overdue books.How do data dictionaries aid in mapping dependencies between data elements?
- The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. a. List all copies of the book title “Lord of the Rings” that are available for borrowing. b. List the names of borrowers who currently have the book title “Lord of the Rings” on loan. c. List the names of borrowers with overdue books.The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. Formulate the following queries in relational algebra and tuple relational calculus: 5.27 List all copies of book titles that are available for borrowing. 5.28 List all copies of the book title “Lord of the Rings” that are available for…The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. Formulate the following queries in relational algebra only. a. How many copies of ISBN “0-321-52306-7” are there? b. How many copies of ISBN “0-321-52306-7” are currently available c. How many times has the book title with ISBN…
- The following tables form part of a Library database held in an RDBMS: Book (ISBN, title, edition, year) BookCopy (copyNo, ISBN, available) Borrower (borrowerNo, borrowerName, borrowerAddress) BookLoan (copyNo, dateOut, dateDue, borrowerNo) where: Book contains details of book titles in the library and the ISBN is the key. BookCopy contains details of the individual copies of books in the library and copyNo is the key. ISBN is a foreign key identifying the book title. Borrower contains details of library members who can borrow books and borrowerNo is the key. BookLoan contains details of the book copies that are borrowed by library members and copyNo/dateOut forms the key. borrowerNo is a foreign key identifying the borrower. Formulate the following queries in relational algebra and tuple relational calculus: a. List all book titles. b. List all borrower details. c.List all book titles published in the year 2012. d. List all copies of book titles that are…calculate_new_balance Given a starting balance (a number), and a list of transaction tuples, calculate the final balance for an account. Transaction tuples are of the shape ("description", amount, "withdrawal") , or ("description", amount, "deposit"). The last entry in the tuple will be either "withdrawal" or "deposit". Every withdrawal decreases the balance of the account by the specified amount, and every deposit increases the balance. The return value is the new account balance, as a number. (which could be negative) Sample calls should look like: >>> calculate_new_balance(100, [("payday", 20, "deposit"), ("new shoes", 50, "withdrawal"), ("illicit winnings", 200, "deposit")])270>>> calculate_new_balance(100, [])1004. Movie Store System This is a system for selling and buying DVDs and videos of movies. There will be three types of users. First the regular customers, they can access the database of DVDs and videos with different types of search. Second there is a group of users that can post DVDs or/and videos to be sold. These users have access to add movies to the database, so that regular customers can search for these movies. When the customer has finished searching for a DVD and/or a video he/she can communicate a message to the seller in order to buy the product from him. The third class of user is the administrator; this user will be in charge of administrating the database and users. The administrator will be in charge of giving and revoking selling privileges to regular customers so that they are able to add videos and DVDs in the database. Use Visual Paradigm to answer the above question with following four UML diagrams: UML Diagram to be used: USE CASE (For Documentation), Class Diagram…
- Using linked list Part 1: Creating C structures to hold crucial information C structure to store course information Course name Course code Semester (Bonus: Choice to automatically create based on current date) Credit Grade C structure to store student information Name Surname Student ID (automatically created based on the current year, program ID, and order of registration, ex: 2023 01 0001 (could be in whatever format you wish)) An array of at most 20 courses taken (will be kept as course C structures) Graduated or Active Bonus: CGPA calculation based on course credits and grades Bonus: Status based on CGPA (ex: High honor, honor, etc.) C structure to store program/ department information These structures will initially be held in an array Program name (ex: Electrical and Electronics Engineering) Program ID, automatically created based on the order of input (ex: 1,2,3) An array of at most 20 students (will be kept as student C structures) Total number of students…*SI schema contains customers that have bought one or more vehicles.They can be classified using the following criteria:Customers that have bought only one car (one-time buyer)Customer that have bought two cars (two-time buyer)Customers that have bought more than two cars (frequent buyer)Using a SINGLE SELECT statement, display a list of customers withtheir names and what type of buyer they are for all those customersthat have bought Mercedes car makes.Data structures concatenate_dict(dict_list:list)->dict This function will be given a single parameter known as the Dictionary List. Your job is to combine all the dictionaries found in the dictionary list into a single dictionary and return it. There are two rules for adding values to the dictionary: 1. You must add key-value pairs to the dictionary in the same order they are found in the Dictionary List. 2. If the key already exists, it cannot be overwritten. In other words, if two or more dictionaries have the same key, the key to be added cannot be overwritten by the subsequent dictionaries. Example: Dictionary List: [{'Z': 6, 'k': 10, 'w': 3, 'I': 8, 'Y': 5}, {'Y': 1, 'Z': 4}, {'X': 2, 'L': 5}] Expected: {'Z': 6, 'k': 10, 'w': 3, 'I': 8, 'Y': 5, 'X': 2, 'L': 5} Dictionary List: [{'z': 0}, {'z': 7}] Expected: {'z': 0} Dictionary List: [{'b': 7}, {'b': 10, 'A': 8, 'Z': 2, 'V': 1}] Expected: {'b': 7, 'A': 8, 'Z': 2, 'V': 1}