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- 1. Molecular Formula: C4H8O2 ¹HNMR in CDC13: Integration values provided next to each expanded peak. 2 9.0 4.1 8.0 4.0 7.0 13CNMR in CDC13: 170.0 200 3.9 6.0 3 5.0 2.0 4.0 60.0 100 1.9 3.0 2.0 3 1.0 1.2 21.0 20.0 19.0 0.0 + 18.0 17.0 16.0 15.0 14.0What structural features of Hydroxypropyl Acrylate (HPA) allow it to be detected by HPLC?1P:18 H.W_cb040d6af52ed4a10c727e8c47881b07.pdf Case 1 A 43-year-old patient suffering from frequent urination and dry tongue was asked by the doctor to analyze RBS, HbA1c and GTT. Results were as follows: RBS = 45 mg\dl 2h GTT = 250 mg\dl HbA1c = 7.5% %3D What interpretation of the result? Case 2 A 35-year-old pregnant woman had a regular check-up and the doctor found the sugar slightly elevated (RBS = 146 mg\dl). What interpretation of the result?
- Mechanism of separation is partitioning SEC O IEX HILIC ONPLCExp 6. IR Spectroscopy OH NaOCI ACOH, 45-50 °C CS Scanned with CamScannerarvc eagle - X C ||| CHM-120- X A ALEKS - As X E Copy of 05 x E Copy of 02 x T llyess El Kc x + https://www-awu.aleks.com/alekscgi/x/Isl.exe/1o_u-lgNslkr7j8P3jH-IBjX3xlvzFZxw7TR-byllKfLwHGamvYq7rHhNGAtExGmPKNhSYT-g1BWbS4C72Z8tGh6... A myRVC O CHEMICAL REACTIONS Solving applied mass percent problems 13- Planni X KZUZETR We're told oxygen is the most common element in the Earth's solid crust. But how much oxygen is there? Let's compare to the amount of oxygen in the Earth's atmosphere, like this: • The radius of the Earth is 6371. km and let's say the crust is the upper 100. km of it. Explanation • The most common minerals in the Earth's crust are feldspars, and albite (NaAlSi3Og) is a typical feldspar. Let's assume the entire crust is made of albite, 3 with a density of 2.6 g/cm³. Rain coming PLEASE REMOVE • Let's model the Earth's atmosphere as a layer on top of the Earth about 100. km thick with an average density of 0.99 g/m³, and which is 23.1% oxygen by mass. Use this information…
- Chemistry what is the ppm shift predictions for the HNMR of Cr(acac)3.Please label importank peaks (isotope peaks, fragments, molecular ions (if present)) please contain location of peaks and likely identity D-glucose C6H1206 (Mass of molecular ion: 180) 100 - MS-NU-9127 80 40 25 50 75 100 12 m/z Source Temperature: 200 °C Sample Temperature: 140 °C Direct, 75 ev 60 20 Relative IntensityDifferent from GCMS, why is an interface needed when coupling HPLC with MS?
- explain the differences between NH4-N and TKN methods.What is needed to understand Homotopic, Enantiotopic, Diasterotopic?Why do not all proteins have the same absorption coefficient (ɛ) at 280 nm? Pick one: a.lt is mainly due to the presence of Asp, Glu, Asn, Gln, Arg and His in the protein b.lt is mainly due to the presence of phenylalanine in the protein c.It is mainly due to the presence of tryptophans and tyrosines in the protein d.The statement is incorrect; all proteins have the same (E) at 280 nm