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- The management of Brawn Engineering is considering three alternatives to satisfy an OSHA requirement for safety gates in the machine shop. Each gate will completely satisfy the requirement, so no combinations need to be considered. The first costs, operating costs, and salvage values over a 5-year planning horizon are shown below. End of Year Gate 1 Gate 2 Gate 3 0 -$15,000 -$19,000 -$24,000 1 -$6,500 -$5,600 -$4,000 2 -$6,500 -$5,600 -$4,000 3 -$6,500 -$5,600 -$4,000 4 -$6,500 -$5,600 -$4,000 5 -$6,500 + $0 -$5,600 + $2,000 -$4,000 + $5,000 What is the future worth of each alternative?Bramble Corp. is considering purchasing one of two new diagnostic machines. Either machine would make it possible for the company to bid on jobs that it currently isn't equipped to do. Estimates regarding each machine are provided below. Original cost Estimated life Salvage value Estimated annual cash inflows Estimated annual cash outflows Click here to view PV tables. Machine A $243,000 8 years -0- $80,000 $35,000 Machine B $317,000 8 years -0- $95,000 $40,000 Calculate the net present value and profitability index of each machine. Assume a 9% discount rate. (Round net present value to theRequired information The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta-Start" does indeed work for every engine produced. Push System $-2,150,000 $-500,000 $100,000 8 years First cost of equipment AOC per Year Salvage Value Estimated Life Pull System $-1,700,000 $-740,000 $125.000 8 years Determine the salvage value for the push system that will make the company indifferent to the two systems. Also, MARR = 12% per year. The salvage value for the push system is determined to be $ in $1000 units.
- Required information The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta-Start" does indeed work for every engine produced. First cost of equipment AOC per Year Salvage Value Estimated Life Pull System $-1,450,000 $-700,000 $120,000 8 years Push System $-2,550,000 $-660,000 $80,000 8 years Determine the salvage value for the push system that will make the company indifferent to the two systems. Also, MARR = 12% per year. The salvage value for the push system is determined to be $ 2351611.32 in $1000 units.Correct only pls. Only the highlighted parts. Npv if pretax cost savings are $100000 per year is -121277. 58. Now how to find the last part.Given the two machines’ data Machine A Machine B First Cost P8,000.00 P14,000.00 Salvage value 0 2,000.00 Annual operation 3,000.00 2,400.00 Annual maintenance 1,200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method, determine the value of alternative A and alternative B: note:round off final answer to 2 decimal ANSWER for ALTERNATIVE A: ANSWER for ALTERNATIVE B:
- The following annual costs are associated with three new extruder machines being considered for use in a Styrofoam cup plant: Data Useful Life, Years First Cost Salvage Value Annual Benefit M&O M&O Gradient X 17 $2,500,000 $105,000 $199,000 $65,000 $16,000 X-TRUD 13 $2,620,000 $109,000 $614,000 $80,000 $14,500 O Choosing SUPR-X is best because it has the highest Annual Benefit Choosing SUPR-X is best because it has the lowest M&O cost in yr1 SUPR-X 7 $2,020,000 $117,000 $671,000 $56,000 $11,000 The company's interest rate (MARR) is 4%. Which extruder should the Styrofoam company choose? Use Annual Cash Flow Analysis and provide the right reason. O Choosing SUPR-X will maximize the EUAB-EAUC; its value is $442,101 higher than X and $62,879 higher than X-TRUD. O Choosing SUPR-X will maximize the EUAB-EAUC; its value is $-38,899 higher than X and $-18,121 higher than X-TRUD.For th below two machines and based on AW analysis which machine we should select? MARR=10% Machine A Machine B 26612 12417 4135 Life, years 3 Answer the below question: B- the AW for machine B= First cost, $ Annual cost, $/year Salvage value, $ 140454 7170 infinite! Required information The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta- Start" does indeed work for every engine produced. First cost of equipment AOC per Year Salvage Value Estimated Life Pull System $-1,550,000 $-620,000 $90,000 8 years Push System $-2,650,000 $-620,000 $50,000 8 years Compare the annual worth of the two systems at MARR = 11% per year. Select the better system. The (Click to select) is determined to be the better system. (Click to select) pull system push system
- Required information The Briggs and Stratton Commercial Division designs and manufacturers small engines for golf turf maintenance equipment. A robotics-based testing system with support equipment will ensure that their new signature guarantee program entitled "Always Insta-Start" does indeed work for every engine produced. First cost of equipment AOC per Year Salvage Value Estimated Life Pull System $-1,950,000 $-680,000 $105,000 8 years Push System $-2,650,000 $-420,000 $60,000 8 years Compare the annual worth of the two systems at MARR = 8% per year. Select the better system. The push system ✓is determined to be the better system.Given the two machines' data Machine A Machine B First Cost P8.000.00 P14,000.00 Salvage value 2.000.00 Annual operation 3,000.00 2,400.00 Annual maintenance 1.200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method, determine the value of alternative A and alternative B:Given the two machines' data Machine A Machine B First Cost P8,000.00 P14,000.00 Salvage value Annual operation 2,000.00 3,000.00 2,400.00 Annual maintenance 1,200.00 1,000.00 Taxes and insurance 3% 3% Life, years 10 15 Money is worth at least 16% Using equivalent uniform annual cost method,determine the valuejof alternative A and alternative B: