What are the states for diodes in the figure below? D1 D2 4 k2 10 V 10 V= O a. D1 off D2 on O b. D1 off D2 off O c. D1 on D2 off O d. D1 on D2 on
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- How is a solid-state diode tested? Explain.a. If you do not go completely around the loop when applying Kirchhoff’s voltage law, then the algebraic sum of the voltages cannot be determined the algebraic sum of the voltages will always be positive the algebraic sum of the voltages will always be negative the algebraic sum is the voltage between the start and finish points b. A p -type semiconductor is a semiconductor doped with impurity atoms whose electron valence is +4 pentavalent impurity atoms trivalent impurity atomsFor the circuit below, assume the diodes operate with a constant voltage drop of .7V, find Vx, Vy, VD4 and ID2. 15V 15V Allt V1 V2 R1 1k IDC 1mA Vx R2 2k ww D1N4002 Vy D1N4002 7D1 D1N4002 D2 D3 R3 1k D4 D1N4002
- 1- ) Determine the output voltage and diode currents ipi and iD2 for the circuit shown for the two values of input voltage V₁ = OV and V1 = 4 V. Assume that diodes have 0.7V constant voltage drop. 5 V1 le iD1 D1 # R1 10k V2 + --1₁ 5V ..e D2 Vo 5k V3 HOE R2 SVAll of the diodes in the following circuit are Silicon w/ forward voltage 0.6V. Determine the value of the current I in amperes if R1 = 100 and R2 = 150 R1 I 10 V R2 KtQ*: Calculate the current through 48 Q resistor in the circuit shown in Figure(i).Assume the diodes to be of silicon and forward resistance of each diode is 1 Q. D D2 48 2 ww 10 V= D4 D3 (i)
- Diodes Are Connected In Series To Share A Total... 21 Question • Two diodes are connected in series to share a total reverse voltage of VD=D 5 KV. Reverse leakage currents of the diodes are ID1=30 mA and Ip2=35 mA. - Find Vp1 and Vp2 for R,=R2=100 k2 - Find R, and R2 for VD1=VD2 R1 VD1 Hint: Is=L,+IRj= I,2+IR2 VD R2 VD2use the constant voltage drop model in analyzing the diode circuit below: 10 92 V₁ (+ M 1 V D₁ If V₁ is -3 V, what would be the state of the diodes? A. D₁ and D₂ are both OFF C B. D₁ is OFF and D₂ is ON - 1 V D₂ C. D₁ is ON and D₂ is OFF D. D₁ and D₂ are both ON + 1092 VoAssuming an ideal diode model for all the diodes in the circuit below, chose the correct state (bias) for each diode. 9kO IN1199C R2 01 18KO IN11990 D3 IN1199C R3 V2 12 V R4 5kQ
- for the circuit shown below (when the diodes are ideal), the values of ID1, and ID2 ipi ip2 D2 Vpi V p2 500 Q V, = 5 V V2 = 3 V is E Vs=5 VQ11) For the shown figure below .Explain the state of the given diodes .Calculate the current and the voltage through each diode. D1 Si D2- Si 1N3491 1N3491 1kQ 12V 3V 1N3491 Si D3 A- II !!!Q3) For the circuit in figure(2) find the current and the voltage for (1k Ohm, 2k Ohm, 3k Ohm) and the voltage on each diode where each diodes are Ge-type: D1 D4 1k Ohm D2 D5 -21 V 2k Ohm D6 -14 V 12V 3k Ohm