Use bond enthalpies in the table below to estimate AH for each of the following reactions.Average bond enthalpy (kJ/mol)Part AC-H: 413N-H: 391O-H: 463F-F: 155C-C: 348N-N: 1630-0: 146C=C: 614N-O: 201O=0: 495Cl-F: 253BrBrBr-C-H+Cl-Cl→ Br- C-Cl+ CI-HBrBrExpress your answer in kilojoules to three significant figures.C-N: 293N-F: 272O-F: 190Cl-Cl: 242C-O: 358N-Cl: 200O-Cl: 203Br-F: 237ΜΕ ΑΣΦ7 0?C=O: 799N-Br: 243O-I: 234Br-Cl: 218C-F: 485H-H: 436Br-Br: 193AH=C-Cl: 328H-F: 567C-Br: 276C-I: 240H-Cl: 431H-Br: 366H-I: 299I-Cl: 208SubmitRequest AnswerI-Br: 175I-I: 151Part BkJConstants | PeriodicHH-C-H+20=00=C=0 + 2 H-O-HHExpress your answer in kilojoules to three significant figures.ΔΗ=ΜΕ ΑΣΦSubmitRequest AnswerProvide FeedbackMacBook Pro20?kJ

Use bond enthalpies in the table below to estimate AH for each of the following reactions. Average bond enthalpy (kJ/mol) Part A Br Br Br-C-H+Cl-Cl→ Br-C-CI+ Cl-H Br Br Express your answer in kilojoules to three significant figures. C-H: 413 N-H: 391 O-H: 463 F-F: 155 C-C: 348 N-N: 163 0-0: 146 C=C: 614 N-O: 201 O=0: 495 Cl-F: 253 C-N: 293 N-F: 272 O-F: 190 Cl-Cl: 242 C-O: 358 N-Cl: 200 O-Cl: 203 Br-F: 237 C=O: 799 N-Br: 243 O-I: 234 Br-Cl: 218 C-F: 485 H-H: 436 Br-Br: 193 AH = C-Cl: 328 H-F: 567 C-Br: 276 H-Cl: 431 C-I: 240 H-Br: 366 H-I: 299 I-I: I-Cl: 208 I-Br: 175 151 ▾ Part B ΜΕ ΑΣΦ Submit Request Answer ? kJ H H-C-H+2 0 0 0=C=0 + 2 H-O-H H Express your answer in kilojoules to three significant figures. ΜΕ ΑΣΦ ΔΗ Submit Request Answer kJ

Use bond enthalpies in the table below to estimate AH for each of the following reactions. Average bond enthalpy (kJ/mol) Part A Br Br Br-C-H+Cl-Cl→ Br-C-CI+ Cl-H Br Br Express your answer in kilojoules to three significant figures. C-H: 413 N-H: 391 O-H: 463 F-F: 155 C-C: 348 N-N: 163 0-0: 146 C=C: 614 N-O: 201 O=0: 495 Cl-F: 253 C-N: 293 N-F: 272 O-F: 190 Cl-Cl: 242 C-O: 358 N-Cl: 200 O-Cl: 203 Br-F: 237 C=O: 799 N-Br: 243 O-I: 234 Br-Cl: 218 C-F: 485 H-H: 436 Br-Br: 193 AH = C-Cl: 328 H-F: 567 C-Br: 276 H-Cl: 431 C-I: 240 H-Br: 366 H-I: 299 I-I: I-Cl: 208 I-Br: 175 151 ▾ Part B ΜΕ ΑΣΦ Submit Request Answer ? kJ H H-C-H+2 0 0 0=C=0 + 2 H-O-H H Express your answer in kilojoules to three significant figures. ΜΕ ΑΣΦ ΔΗ Submit Request Answer kJ

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter19: The Chemistry Of The Main-group Elements

Section: Chapter Questions

Problem 68QRT

See similar textbooks

Similar questions

The heat of neutralization, Hneut, can be defined as the amount of heat released (or absorbed), q, per mole of acid (or base) neutralized. Hneut for nitric acid is -52 kJ/mol HNO3. At 27.3C, 50.00 mL of 0.743M HNO3 is neutralized by 1.00 M Sr(OH)2 in a coffee-cup calorimeter. (a) How many mL of Sr(OH)2 were used in the neutralization? (b) What is the final temperature of the resulting solution? (Use the assumptions in Question 11.)
Although the gas used in an oxyacetylene torch (Figure 5.7) is essentially pure acetylene, the heat produced by combustion of one mole of acetylene in such a torch is likely not equal to the enthalpy of combustion of acetylene listed in Table 5.2. Considering the conditions for which the tabulated data are reported, suggest an explanation.
Calculate the enthalpy change when 1.0(1 g of methane is burned in excess oxygen according to the reaction CH,(g) 4- 2O2(g) ->CO2(g) + H-CH/) 1H = -891 kJ/mol
The thermochemical equation for the burning of methane, the main component of natural gas, is CH4(g)+2O2(g)CO2(g)+2H2O(l)H=890kJ (a) Is this reaction endothermic or exothermic? (b) What quantities of reactants and products are assumed if H = 890 kJ? (c) What is the enthalpy change when 1.00 g methane burns in an excess of oxygen?
9.99 The chemical reaction BBr3(g)+BCl3(g)BBr2Cl(g)+BCl2Br(g) , has an enthalpy change very close to zero. Using Lewis structures of the molecules, all of which have a central boron atom, provide a molecular-level description of why H for this reaction might be very small.
Hydrazine, N2H4, is a colorless liquid used as a rocket fuel. What is the enthalpy change for the process in which hydrazine is formed from its elements? N2(g)+2H2(g)N2H4(l) Use the following reactions and enthalpy changes: N2H4(l)+O2(g)N2(g)+2H2O(l);H=622.2kJH2(g)+12O2(g)H2O(l);H=285.8kJ
The enthalpy change for the reaction of hydrogen gas with fluorine gas (o produce hydrogen fluoride is 542 U for the equation as written: mg src=Images/HTML_99425-10-41QAP_image001.jpg alt="" align="top"/> l type='a'> What is the enthalpy change per mole of hydrogen fluoride produced? Is the reaction exothermic or endothermic as written? What would be the enthalpy change for the reverse of the given equation (that 1%, for the decomposition of HF into its constituent elements)?
The standard enthalpies of formation for S(g), F(g), SF4(g), and SF6(g) are +278.8, +79.0, 775, and +1209 KJ/mol, respectively. a. Use these data to estimate the energy of an SF bond. b. Compare your calculated value to the value given in Table 3-3. What conclusions can you draw? c. Why are the Hf values for S(g) and F(g) not equal to zero, since sulfur and fluorine are elements?