Use a graphing utility to find the inverse, if it exists, of the given matrix. Select the correct choice below and, if necessary, fill in the answer box within your choice. OA. The inverse of the matrix 25 57 - 17 21-2 8 is -9 40 27 (Type an integer or decimal for each matrix element. Round to two decimal places as needed.) O B. The matrix has no inverse. 25 57 - 17 21 - 2 8 -9 40 27 ४ Use the given inverse of the coefficient matrix to solve the following system of equations. -0.06 -0.02 0.56 25x + 62y - 12z = 10 0.10 0.07 -0.75 18x12y + 7z= -9 0.32 0.31 -2.72 5x + 6y- z = 13 The solution is x = y = and z= (Round to two decimal places as needed.)
Use a graphing utility to find the inverse, if it exists, of the given matrix. Select the correct choice below and, if necessary, fill in the answer box within your choice. OA. The inverse of the matrix 25 57 - 17 21-2 8 is -9 40 27 (Type an integer or decimal for each matrix element. Round to two decimal places as needed.) O B. The matrix has no inverse. 25 57 - 17 21 - 2 8 -9 40 27 ४ Use the given inverse of the coefficient matrix to solve the following system of equations. -0.06 -0.02 0.56 25x + 62y - 12z = 10 0.10 0.07 -0.75 18x12y + 7z= -9 0.32 0.31 -2.72 5x + 6y- z = 13 The solution is x = y = and z= (Round to two decimal places as needed.)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter9: Systems Of Equations And Inequalities
Section: Chapter Questions
Problem 34RE
Related questions
Question
Please help me to solve the problem on the screenshots.
Transcribed Image Text:Use a graphing utility to find the inverse, if it exists, of the given matrix.
Select the correct choice below and, if necessary, fill in the answer box within your choice.
OA.
The inverse of the matrix
25 57 - 17
21-2 8 is
-9 40 27
(Type an integer or decimal for each matrix element. Round to two decimal places as needed.)
O B. The matrix has no inverse.
25 57 - 17
21 - 2
8
-9 40
27
४
Transcribed Image Text:Use the given inverse of the coefficient matrix to solve the following system of equations. -0.06 -0.02 0.56
25x + 62y - 12z = 10
0.10
0.07 -0.75
18x12y + 7z= -9
0.32
0.31 -2.72
5x + 6y-
z = 13
The solution is x =
y =
and z=
(Round to two decimal places as needed.)
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