The Problem: You need to increment a variable in the fastest possible way.
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The Problem: You need to increment a variable in the fastest possible way.
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- Python Assignment: In India McDonald's has the n number of customers and they are famous for their taste and quality so they plan to Organise the challenge for foody people. What is the challenge is?| you have taken a food challenge from the Chef and now you have to eat directly the Y burgers. You will eat as follows: At the first minute you will eat exactly the X burgers and every minute after that you will eat twice the number of burgers you ate the minute before. As you can get tired of food, Chef also lets you take a break from eating for one minute. When you start eating again after a break, your food streaks are reset, which means that in the first minute after the break you will eat X burgers and every minute after that you will eat the burgers you ate twice the last minute. Allow a1, a2, ., let it be your meal length in minutes. The cook needs to have all the ai different in pairs. Get the minimum number of minutes you need to eat Y burgers directly or decide that it is not…15. Speed Conversion ChartYour friend Amanda, who lives in the United States, just bought an antique European sports car. The car’s speedometer works in kilometers per hour. The formulafor converting kilometers per hour to miles per hour is:MPH = KPH * 0.6214In the formula, MPH is the speed in miles per hour and KPH is the speed in kilometersper hour. Amanda is afraid she will get a speeding ticket, and has asked you to write aprogram that displays a list of speeds in kilometers per hour with their values convertedto miles per hour. The list should display the speeds from 60 kilometers per hourthrough 130 kilometers per hour, in increments of 5 kilometers per hour. (In otherwords, it should display 60 kph, 65 kph, 70 kph, and so forth, up through 130 kph.) made in visual studio 2017The following statement should determine if x is not greater than 20. What is wrong with it?
- Note: You are not allowed to use more than seven variables in your program.Can you declare a variable as int and later redeclare it as double?1: If the variable divisor is not zero, divide the variable dividend by the divisor, and store theresult in quotient. If divisor is zero, assign it to quotient. Then print all the variables. [ Assumethat divisor and dividend are integers and quotient is a double ]
- Note: You are not allowed to use more than four variables in your program.Python: numpy def serial_numbers(num_players):"""QUESTION 2- You are going to assign each player a serial number in the game.- In order to make the players feel that the game is very popular with a large player base,you don't want the serial numbers to be consecutive. - Instead, the serial numbers of the players must be equally spaced, starting from 1 and going all the way up to 100 (inclusive).- Given the number of players in the system, return a 1D numpy array of the serial numbers for the players.- THIS MUST BE DONE IN ONE LINEArgs:num_players (int)Returns:np.array>> serial_numbers(10)array([1. 12. 23. 34. 45. 56. 67. 78. 89. 100.])>> serial_numbers(12)array([1. 10. 19. 28. 37. 46. 55. 64. 73. 82. 91. 100.])""" # print(serial_numbers(10)) # print(serial_numbers(12))Question: Party budget planning - complex Prompt the user to enter their current budget and the number of people who need to share a meal. You are ordering food from a restaurant that has two menu items: Tacos $4 Empanadas $3 Calculate and print out all the options of meals where the budget is used entirely(where possible) and each person has an equal number of items to eat. They may eat different things, but everyone gets the same number of food items, e.g. 2 tacos or 1 empanada and 1 taco or 2 empanadas. Hints: Here are some things that might help you in your solution. If total items purchased does not equally divide by the number of diners, then abandon that combination. It may help to calculate the max number of empanadas that the budget can buy and also the max number of tacos that the budget could buy. These can be thought of as upper bounds in your loops. In your solution, keep track of items per person Also, keep track of total number of viable solutions, as that might…
- In Python Text-based adventure game: Pretend you are creating a text-based adventure game. At different points in the game, you want the user to select to fight, run, or hide from certain enemies. The selection variable must be sent as an argument into the choice() function. The user should enter 1 to fight, 2 to run, or 3 to hide in the main(). The choice() function should print one of the three options. Add an if statement in the choice() function to make the correct selection.Question: Party budget planning - complex Prompt the user to enter their current budget and the number of people who need to share a meal. You are ordering food from a restaurant that has two menu items: Tacos $4 Empanadas $3 Calculate and print out all the options of meals where the budget is used entirely(where possible) and each person has an equal number of items to eat. They may eat different things, but everyone gets the same number of food items, e.g. 2 tacos or 1 empanada and 1 taco or 2 empanadas. Hints: Here are some things that might help you in your solution. If total items purchased does not equally divide by the number of diners, then abandon that combination. It may help to calculate the max number of empanadas that the budget can buy and also the max number of tacos that the budget could buy. These can be thought of as upper bounds in your loops. In your solution, keep track of items per person Also, keep track of total number of viable solutions, as that might…Provide description on how to use the code. Code is located below: # initialize a flag variable with 0flag = 0 # loop will execute till flag is 0 in the sense loop will execute codewhile flag == 0 : #until amount is greater then costcost = float(input("Enter the cost: ")) # take input cost and convert to floating data typeamount = float(input("Enter the amount given(should be greater than cost): ")) # take inputif amount < cost :print("Amount should be greater than cost.") #print statement saying enter Amount thatelse:flag = 1 # when amount entered by user greater then cost flag is set to 1 and while loop will not execute change = amount-cost #stored difference between amount and cost to change variableprint(f"The change to be given is ${change}") #print the value of change variable twenty=0 #intializing all possible coin/ notes to 0ten=0five=0single=0quarter=0dime=0nickel=0penny=0 while change>=20 : #loop will execute until change become less then 20. this loop execute for…