The position of a particle is given by s = 0.33t3 - 0.74t2 - 2.82t + 5.61, where s is in feet and the time t is in seconds. Plot thedisplacement, velocity, and acceleration as functions of time for the first 8 seconds of motion. After you have the plots, answer thequestions as a check on your work.-+ s, ft+1-1Questions:When t = 1.8 sec, v=ft/sec, a=ift/sec2ft/sec, a=ft/sec?When t = 5.4 sec, v=iThe positive time at which the particle changes direction is isec.

Consider the given situation S=0.33t3-0.74t2-2.82t+5.61 ftS=distance in feett=time in…

Answered: The position of a particle is given by…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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(a)The force acting on a particle varies as in the shown figure. Find the work done by the force on the particle as it moves (a) from x-0 to x= 8 m,(b) from x-8m to x= 10m.c) from x=0 to x-10. F(N) 4 x(m) 2 46 8 10 -2
The motion of a particle is defined by x = 6t"4 - 2t°3 - 12t^2 + 3t + 3, when x and t are expressed in meters and seconds, respectively. • When a = 0, determine the time • When a= 0, determine the velocity When a = 0, determine the position
The motion of a particle is defined by the relation x = 2t4 – 6t3 + 3t + 3, where x and t - are expressed in meters and seconds, respectively. Determine the time, the = 0. position, and the velocity when a = 0.
Start Siide Show B Print to PDF Commer • 1. a. How far does a particle travel between zero to four seconds if its position is given by: S (t) = t4 8t2 ( ft) Note use time intervals 0→2 and 2→4 b. Find the acceleration when velocity is zero C. Find the average velocity at t = 1s and t = 3 s %3D d. Find the average acceleration att = 0 andt = 2 s
Find ??, ?? and ?. NOTE: ?? and ?? in mm/mm and ? in radians. Use 3 decimal places in every solved value.
The motion of a particle is defined by x = 6t – 2t³ – 12² – 3t + 3, where x and t are expressed in meters and seconds, respectively. Determine the time, the position, and the velocity when a = 0. -
UPVOTE will be given! Please write the complete solutions legibly. No long explanation needed. Answer in 2 decimal places. Dynamics of Rigid Bodies The rotation of the 0.9-m arm OA about O is defined by the relation Eq. (1), where is θ expressed in radians and t in seconds. Collar B slides along the arm in such a way that its distance from O is Eq. (2), where r is expressed in meters and t in seconds. After the arm OA has rotated through 30°, determine the relative acceleration with respect to the arm (m/s2).(Answer in 2 decimal places) θ = 0.15t2 is Eq'n (1) r = 0.9 - 0.12t2 is Eq'n (2)
By direct integration, determine the moments of inertia of the triangular area about the x- and x'-axes. 8" 20" Answers: in 4 Ix = in 4 Save for Later Attempts: 0 of 1 used Submit Answer
UPVOTE will be given! Please write the complete solutions legibly. No long explanation needed. Answer in 2 decimal places. Dynamics of Rigid Bodies The rotation of the 0.9-m arm OA about O is defined by the relation Eq. (1), where is θ expressed in radians and t in seconds. Collar B slides along the arm in such a way that its distance from O is Eq. (2), where r is expressed in meters and t in seconds. After the arm OA has rotated through 30°, determine the acceleration (m/s2).(Answer in 2 decimal places) θ = 0.15t2 is Eq'n (1) ; r = 0.9 - 0.12t2 is Eq'n (2)
UPVOTE will be given! Please write the complete solutions legibly. No long explanation needed. Answer in 2 decimal places. Dynamics of Rigid Bodies The rotation of the 0.9-m arm OA about O is defined by the relation Eq. (1), where is θ expressed in radians and t in seconds. Collar B slides along the arm in such a way that its distance from O is Eq. (2), where r is expressed in meters and t in seconds. After the arm OA has rotated through 30°, determine the velocity of the collar (m/s). θ = 0.15t2 is Eq'n (1) ; r = 0.9 - 0.12t2 is Eq'n (2)
4. An object's position is described by the followving polynomial for O to 10 s. = 2t^4 4t*3 12t 2 Where s is in meters, t is in seconds, and positive is forward. a. The object's velocity function is b. The objects velocity whent = 5 is m/s The object's acceleration function is d. The object's acceleration t= 8 is m/s 2 e. The object's velocity when t=8 is m/s f. Time when the object changes direction is 2 places g. Point at which the object changes direction is (round off to nearest ones)
Suppose that vc=4.5 ft/s. (Figure 1) Figure 1 ft B A 3966666 Te 3 ft < 1 of 1 Part A Determine the angular velocity of link AB at the instant 0 = 30° measured counterclockwise. Express your answer in radians per second to three significant figures. Enter positive value if the angular velocity is counterclockwise and negative value if the angular velocity is clockwise. WAB = Submit Part B 17 ΑΣΦ 跖 ↓↑ vec X Incorrect; Try Again; 4 attempts remaining WBC = Previous Answers Request Answer ? Determine the angular velocity of link BC at the instant 0 = 30° measured counterclockwise. Express your answer in radians per second to three significant figures. Enter positive value if the angular velocity is counterclockwise and negative value if the angular velocity is clockwise. —| ΑΣΦ. 11 | vec ww rad/s ? rad/s

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