The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: 3H₂O + 3Br₂ +16Br + 10,+ 6H* The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: Ba²+ + 210, Ba(10₂); In the analysis of a 1.59-g sample, 0.0538 g of barium iodate was recovered. Express the results of thic analysis as percent potassium iodida

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Chapter14: Chemical Equilibrium
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The iodide in a sample that also contained chloride was converted to iodate by treatment
with an excess of bromine:
3H,0 + 3Br, +-→ 6Br + 10," + 6H*
The unused bromine was removed by boiling; an excess of barium ion was then added
to precipitate the iodate:
Ba* + 210, - Ba(10,);
In the analysis of a 1.59-g sample, 0.0538 g of barium iodate was recovered. Express
the results of this analysis as percent potassium iodide.
Transcribed Image Text:The iodide in a sample that also contained chloride was converted to iodate by treatment with an excess of bromine: 3H,0 + 3Br, +-→ 6Br + 10," + 6H* The unused bromine was removed by boiling; an excess of barium ion was then added to precipitate the iodate: Ba* + 210, - Ba(10,); In the analysis of a 1.59-g sample, 0.0538 g of barium iodate was recovered. Express the results of this analysis as percent potassium iodide.
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